An organism has 27000bp genome. Consider id all the nucleotides are en...
Given: Genome size = 27000bp
We know, 3 bp of DNA encodes for 1 amino acid = 110Da
So, 270bp of DNA encodes = 90 amino acids =90 × 110 = 9900Da = 9.9kD 410kDa
For, 50kDa protein, the required DNA size would be = (270/10) × 50 = 1.35 kb.
Here, the total length of the DNA = 27000. So maximum number of proteins encoded from the DNA is 27000bp/1350 bp = 20.
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An organism has 27000bp genome. Consider id all the nucleotides are en...
Calculating the Maximum Number of Protein Molecules Encoded by the Genome
Given data:
- Genome size: 27000 bp
- Nucleotides encoded to protein molecules
- Each protein molecule size: 50 kD
To calculate the maximum number of protein molecules encoded by the genome, we need to follow these steps:
Step 1: Convert bp to kbp
- 1 bp = 0.001 kbp
- Genome size in kbp = 27000 x 0.001 = 27 kbp
Step 2: Calculate the number of codons
- Each codon is made up of three nucleotides
- Number of codons = (27 kbp x 1000) / 3 = 9000 codons
Step 3: Calculate the number of amino acids
- Each codon codes for one amino acid
- Number of amino acids = 9000 amino acids
Step 4: Calculate the number of protein molecules
- Each protein molecule is made up of a specific sequence of amino acids
- To calculate the maximum number of protein molecules encoded by the genome, we need to assume that each amino acid sequence is unique and does not repeat
- The maximum number of protein molecules = the number of possible amino acid sequences
- The number of possible amino acid sequences = 20^9000
- 20 is the number of different amino acids that can be used to build a protein molecule
- 9000 is the number of amino acids encoded by the genome
- Using the formula, we get: 20^9000 = 1.35 x 10^11783
Step 5: Convert the number of protein molecules to a more manageable form
- The number of protein molecules is extremely large and not practical to work with
- To get a more manageable number, we can take the logarithm base 10 of the number
- log10(1.35 x 10^11783) = 11783 log10(1.35 x 10)
- log10(1.35 x 10) = log10(1.35) + log10(10) = 0.13 + 1 = 1.13
- 11783 log10(1.35 x 10) = 13285.79
Step 6: Calculate the maximum number of protein molecules
- The maximum number of protein molecules = 10^(13285.79)
- Using a calculator, we get: 1.12 x 10^13285
Final Answer:
The maximum number of protein molecules encoded by the genome is approximately 20.