The loop transfer function of a system is given by G(s) H(s) =10e-Ls/s...
Answer: b
Explanation: – π/2-180/π*L*5 = -π
5L =π/2
L =π/10.
View all questions of this testThe loop transfer function of a system is given by G(s) H(s) =10e-Ls/s...
To find the value of the dead time L, we need to determine the phase shift caused by the transfer function G(s) H(s) at the phase crossover frequency.
The phase crossover frequency is the frequency at which the phase shift of the transfer function is equal to -180 degrees or π radians.
Given that the transfer function is G(s) H(s) = 10e^(-Ls)/s, we can express it in polar form as:
G(s) H(s) = 10e^(-Ls)/s = 10/s * e^(-Ls)
The magnitude of the transfer function is 10/s, which is a constant value.
To find the phase shift caused by the exponential term e^(-Ls), we need to evaluate it at the phase crossover frequency:
e^(-Ls) = e^(-L * 5) = e^(-5L)
Since the magnitude of e^(-5L) is always equal to 1, the phase shift caused by this term is zero.
Therefore, the phase shift caused by the transfer function G(s) H(s) is solely determined by the 10/s term.
At the phase crossover frequency, the magnitude of 10/s is 10/5 = 2.
Since the phase shift at the phase crossover frequency is -180 degrees or π radians, we can write the equation:
arctan(0/2) = -π
This equation is not solvable because the arctan(0/2) is equal to 0, not -π.
From this analysis, we can conclude that the transfer function G(s) H(s) = 10e^(-Ls)/s does not have a phase crossover frequency of 5 rad/s.
Therefore, there is not enough information provided to determine the value of the dead time L.
The loop transfer function of a system is given by G(s) H(s) =10e-Ls/s...
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