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A, B and C can do a piece of work in 15,12,and 20 days respectively. They started the work together, but c left after 2 days. In how many days will the remaining work be completed by A and B.?
Most Upvoted Answer
A, B and C can do a piece of work in 15,12,and 20 days respectively. T...
Solution:

Given, A, B and C can do a piece of work in 15, 12, and 20 days respectively.

Let the total work be 60 units (LCM of 15, 12 and 20)

Hence, A can do 4 units of work per day, B can do 5 units of work per day and C can do 3 units of work per day.

Step 1: Calculation of work done in the first two days
A and B and C worked together for two days. Therefore, the work done in the first two days is:

2 (A + B + C) = 2 (4 + 5 + 3) = 24 units.

Step 2: Calculation of work remaining after two days
The work remaining after two days is:

60 – 24 = 36 units.

Step 3: Calculation of time taken by A and B to complete the remaining work
Now, A and B are left to complete the remaining work of 36 units.

Since A can do 4 units of work per day and B can do 5 units of work per day, their combined rate of work is 4 + 5 = 9 units per day.

Therefore, the time taken by A and B to complete the remaining work is:

Time = Work/Rate = 36/9 = 4 days.

Therefore, A and B will take 4 more days to complete the remaining work.

Hence, the total time taken to complete the work is 2 + 4 = 6 days.
Community Answer
A, B and C can do a piece of work in 15,12,and 20 days respectively. T...
4 days.
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A, B and C can do a piece of work in 15,12,and 20 days respectively. They started the work together, but c left after 2 days. In how many days will the remaining work be completed by A and B.?
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