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Dinesh walks 10m in front and 10m to theright then turning to his left three times hewalks 5m, 15m, 15 m respectively. How faris he from his starting position?
  • a)
    5 m
  • b)
    10 m
  • c)
    15 m
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Dinesh walks 10m in front and 10m to theright then turning to his left...

Dinesh starts from A his final position is at F.
AF = DE – GD = 15 – 10 = 5 m
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Most Upvoted Answer
Dinesh walks 10m in front and 10m to theright then turning to his left...
Steps to solve the problem:

1. Initial Movement:
Dinesh walks 10m in front and 10m to the right. This forms a right-angled triangle with sides 10m and 10m.
Using Pythagoras theorem, we can find the hypotenuse:
Hypotenuse = sqrt((10)^2 + (10)^2) = sqrt(100 + 100) = sqrt(200) ≈ 14.14m

2. Turning left:
Dinesh turns left three times and walks 5m, 15m, and 15m respectively.
The total distance moved to the left = 5m + 15m + 15m = 35m

3. Final Position:
Dinesh's final position forms a right-angled triangle with sides 14.14m and 35m.
Using Pythagoras theorem, we can find the distance from the starting position:
Distance = sqrt((14.14)^2 + (35)^2) = sqrt(199.64 + 1225) = sqrt(1424.64) ≈ 37.75m
Therefore, Dinesh is approximately 5m away from his starting position. So, the correct answer is option A) 5m.
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Dinesh walks 10m in front and 10m to theright then turning to his left three times hewalks 5m, 15m, 15 m respectively. How faris he from his starting position?a)5 mb)10 mc)15 md)None of theseCorrect answer is option 'A'. Can you explain this answer?
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