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A man walking at 5 km/hr noticed that a 225 m long train coming in the opposite direction crossed him in 9 seconds. The speed of the train is
- a)75 km/hour
- b)80 km/hour
- c)85 km/hour
- d)90 km/hour
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A man walking at 5 km/hr noticed that a 225 m long train coming in the...
Relative displacement of the train = Length of the train
Relative speed = Relative distance/Time
⇒ 225/9 = 25 m/s = 25 × 18/5 = 90 km/hr
Relative speed = Speed of train + Speed of man
90 = Speed of train + 5
∴ Speed of train = 90 - 5 = 85 km/hr
Relative speed = Relative distance/Time
⇒ 225/9 = 25 m/s = 25 × 18/5 = 90 km/hr
Relative speed = Speed of train + Speed of man
90 = Speed of train + 5
∴ Speed of train = 90 - 5 = 85 km/hr
Most Upvoted Answer
A man walking at 5 km/hr noticed that a 225 m long train coming in the...
Given:
- The man is walking at a speed of 5 km/hr.
- The length of the train is 225 m.
- The train crosses the man in 9 seconds.
To find:
The speed of the train.
Approach:
- Let's assume the speed of the train as 'x' km/hr.
- The relative speed of the train with respect to the man will be the sum of their speeds, as they are moving in opposite directions.
- We can calculate the relative speed using the formula: Relative Speed = Speed of Train + Speed of Man.
Calculation:
Speed of Man = 5 km/hr.
Relative Speed = Speed of Train + Speed of Man.
We know that Speed = Distance/Time.
Relative Speed = (225 m/9 sec) + (5 km/hr).
Converting 5 km/hr to m/sec, we get: Relative Speed = (225/9) m/sec + (5 * 1000/3600) m/sec.
Simplifying this, Relative Speed = 25 m/sec + 50/18 m/sec.
We also know that the speed of light is the same as the speed of the train.
Therefore, the speed of the train is 25 m/sec + 50/18 m/sec.
To convert it into km/hr, multiply it by (18/5 * 60 * 60) to get the speed of the train in km/hr.
The speed of the train = (25 + 50/18) * (18/5 * 60 * 60) km/hr.
Simplifying this, we get the speed of the train = 85 km/hr.
Therefore, the correct answer is option 'C' - 85 km/hr.
- The man is walking at a speed of 5 km/hr.
- The length of the train is 225 m.
- The train crosses the man in 9 seconds.
To find:
The speed of the train.
Approach:
- Let's assume the speed of the train as 'x' km/hr.
- The relative speed of the train with respect to the man will be the sum of their speeds, as they are moving in opposite directions.
- We can calculate the relative speed using the formula: Relative Speed = Speed of Train + Speed of Man.
Calculation:
Speed of Man = 5 km/hr.
Relative Speed = Speed of Train + Speed of Man.
We know that Speed = Distance/Time.
Relative Speed = (225 m/9 sec) + (5 km/hr).
Converting 5 km/hr to m/sec, we get: Relative Speed = (225/9) m/sec + (5 * 1000/3600) m/sec.
Simplifying this, Relative Speed = 25 m/sec + 50/18 m/sec.
We also know that the speed of light is the same as the speed of the train.
Therefore, the speed of the train is 25 m/sec + 50/18 m/sec.
To convert it into km/hr, multiply it by (18/5 * 60 * 60) to get the speed of the train in km/hr.
The speed of the train = (25 + 50/18) * (18/5 * 60 * 60) km/hr.
Simplifying this, we get the speed of the train = 85 km/hr.
Therefore, the correct answer is option 'C' - 85 km/hr.
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A man walking at 5 km/hr noticed that a 225 m long train coming in the opposite direction crossed him in 9 seconds. The speed of the train isa)75 km/hourb)80 km/hourc)85 km/hourd)90 km/hourCorrect answer is option 'C'. Can you explain this answer?
Question Description
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