The sum of the digits of a two number is 9. If 9 is subtracted from th...
Let the unit’s digit be x.
Ten’s digit = 9 – x
Number = 10 (9 – x) + 1(x)
= 90 – 10x + x= 90 – 9x
90 – 9x – 9 = x(10) + 1(9 – x)
⇒ 81 – 9x = 10x + 9 – x
⇒ 81 – 9x = 9x + 9
⇒ 18x = 72 ⇒ x = 4
Number = 90 – 9 × 4 = 90 – 36 = 54
The sum of the digits of a two number is 9. If 9 is subtracted from th...
Explanation:
Let's assume that the two digits are x and y.
According to the question, the sum of the digits is 9, so we can write:
x + y = 9 ---(1)
If 9 is subtracted from the number, its digits are interchanged. This means that the original number is a multiple of 9. Let's represent the original number as 10x + y.
When 9 is subtracted from the original number, we get:
10x + y - 9 = 10y + x
Simplifying the above equation, we get:
9x - 9y = 9(x - y) = 9
Dividing both sides by 9, we get:
x - y = 1 ---(2)
Now, we have two equations (1) and (2) with two variables (x and y). We can solve for x and y using these equations.
Adding equations (1) and (2), we get:
2x = 10
x = 5
Substituting the value of x in equation (1), we get:
y = 4
Therefore, the two digits are 5 and 4, and the original number is 54.
Hence, the correct answer is option A.