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The size of a beta sheet (in nm) obtained from the translation of a 3000 bp open reading frame of encoding DNA will be ___________ [Answer in integer]
    Correct answer is '350'. Can you explain this answer?
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    The size of a beta sheet (in nm) obtained from the translation of a 30...
    3000 bp ORF will encode for a peptide encoding 3000/3 = 1000 amino acids. The average distance between amino acids in beta sheet in a peptide is 3.5 Angstrom, hence total length of peptide will be
    1000 × 3.5 = 3500 angstrom or 350 nm.
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    The size of a beta sheet (in nm) obtained from the translation of a 3000 bp open reading frame of encoding DNA will be ___________ [Answer in integer]Correct answer is '350'. Can you explain this answer?
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