Two rabbits start running towards each other, one from A to B and another from B to A. They cross each other after one hour and the first rabbit reaches B, 5/6 hour before the second rabbit reaches A. If the distance between A and B is 50 km. what is the speed of the slower rabbit?a)20kmphb)10kmphc)15kmphd)25 kmphCorrect answer is option 'A'. Can you explain this answer?

Question

Answer

Let second rabbit takes x hr with speed s2

First rabbit takes x-5/6 hr with speed s1

Total distance = 50km

S1 = 50/(x-(5/6))

S2= 50/x

As they cross each other in 1hr…

Total speed = s1 + s2

Now, T = D / S

50/(s1+s2) = 1

x = 5/2, 1/3

Put x= 5/2 in s2 –> 20km/hr

Answer

Let second rabbit takes x hr with speed s2
First rabbit takes x-5/6 hr with speed s1
Total distance = 50km
S1 = 50/(x-(5/6))
S2 = 50/x
As they cross each other in 1hr…
Total speed = s1 + s2
Now, T = D / S
50/(s1+s2) = 1
x = 5/2, 1/3
Put x = 5/2 in s2 –> 20km/hr

Answer

Problem Statement:

Two rabbits start running towards each other, one from A to B and another from B to A. They cross each other after one hour and the first rabbit reaches B, 5/6 hour before the second rabbit reaches A. If the distance between A and B is 50 km. what is the speed of the slower rabbit?

Solution:

Let's assume the speed of the faster rabbit be x kmph and the slower rabbit be y kmph.

We know that distance = speed × time

So, the distance traveled by the faster rabbit in 1 hour = x kmph × 1 hr = x km

Similarly, the distance traveled by the slower rabbit in 1 hour = y kmph × 1 hr = y km

When they cross each other, they together traveled a distance equal to the sum of the distance traveled by both the rabbits. Therefore,

x + y = 50 km --- (1)

Now, we know that the first rabbit reaches B, 5/6 hour before the second rabbit reaches A. So, the time taken by the faster rabbit to reach B = 1 hour - 5/6 hour = 1/6 hour.

We also know that the distance traveled by the faster rabbit to reach B is equal to the distance between A and B, i.e., 50 km. So, we can find the speed of the faster rabbit using the formula:

Speed = distance ÷ time

Therefore, x = 50 km ÷ (1/6) hr = 300 kmph

Now, we can use this value of x in equation (1) to find the value of y:

x + y = 50 km

300 kmph + y = 50 km

y = 50 km - 300 kmph

y = -250 kmph (which is not possible)

So, there must be some mistake in our assumption that the faster rabbit's speed is x kmph. Let's assume that the speed of the slower rabbit is x kmph and the faster rabbit's speed is y kmph.

Using the same logic as above, we can write:

x + y = 50 km --- (1)

And, the time taken by the slower rabbit to reach A = 1 hour - 5/6 hour = 1/6 hour.

Therefore,

x = 50 km ÷ (1/6) hr = 300 kmph

Now, we can use this value of x in equation (1) to find the value of y:

x + y = 50 km

300 kmph + y = 50 km

y = 50 km - 300 kmph

y = -250 kmph (which is not possible)

So, there must be some mistake in our assumption that the slower rabbit's speed is y kmph. Let's assume that the speed of the slower rabbit is y kmph and the faster rabbit's speed is x kmph.

Using the same logic as above, we can write:

x + y = 50 km --- (1)

And, the time taken by the faster rabbit to reach B = 1 hour - 5/6 hour = 1/6 hour.

Therefore,

x = 50 km ÷ (1/6) hr = 300 kmph

Now, we can use this value of x in equation (1) to find the value of y:

Answer

Let second rabbit takes x hr with speed s2
First rabbit takes x-5/6 hr with speed s1
Total distance = 50km
S1 = 50/(x-(5/6))
S2 = 50/x
As they cross each other in 1hr…
Total speed = s1 + s2
Now, T = D / S
50/(s1+s2) = 1
x = 5/2, 1/3
Put x = 5/2 in s2 –> 20km/hr

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