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Determine the complex power for the given values in question.
Q. Vrms = 220 V, P = 1 kW, |Z| = 40 Ω (inductive)
Q. Vrms = 220 V, P = 1 kW, |Z| = 40 Ω (inductive)
- a)1000 - j 681.25 VA
- b)1000 + j 681.25 VA
- c)681.25 + j1000 VA
- d)681.25 - j1000 VA
Correct answer is option 'B'. Can you explain this answer?
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Determine the complex power for the given values in question.Q. Vrms =...
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Determine the complex power for the given values in question.Q. Vrms =...
To determine the complex power, we need to find the current and impedance.
Given:
Vrms = 220 V (root mean square voltage)
P = 1 kW (active power)
|Z| = 40 (magnitude of impedance)
First, let's find the current (I) using the formula for power:
P = Vrms * I * cos(θ)
Where θ is the phase angle between the voltage and current.
Since the power factor (cos(θ)) is not given, we'll assume it to be 1 (which means a purely resistive load).
1 kW = 220 V * I * 1
I = 1 kW / 220 V
I ≈ 4.545 A
Next, let's find the impedance (Z) using the magnitude given:
|Z| = 40
Since we assumed a purely resistive load, the impedance is purely real and equal to the resistance (R):
|Z| = R
R = 40 Ω
Now, we can find the complex power (S) using the formula:
S = Vrms * I^* = Vrms * I
Where I^* is the complex conjugate of the current.
S = 220 V * 4.545 A
S ≈ 1000 VA
Therefore, the complex power for the given values is approximately 1000 VA.
Given:
Vrms = 220 V (root mean square voltage)
P = 1 kW (active power)
|Z| = 40 (magnitude of impedance)
First, let's find the current (I) using the formula for power:
P = Vrms * I * cos(θ)
Where θ is the phase angle between the voltage and current.
Since the power factor (cos(θ)) is not given, we'll assume it to be 1 (which means a purely resistive load).
1 kW = 220 V * I * 1
I = 1 kW / 220 V
I ≈ 4.545 A
Next, let's find the impedance (Z) using the magnitude given:
|Z| = 40
Since we assumed a purely resistive load, the impedance is purely real and equal to the resistance (R):
|Z| = R
R = 40 Ω
Now, we can find the complex power (S) using the formula:
S = Vrms * I^* = Vrms * I
Where I^* is the complex conjugate of the current.
S = 220 V * 4.545 A
S ≈ 1000 VA
Therefore, the complex power for the given values is approximately 1000 VA.
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Determine the complex power for the given values in question.Q. Vrms = 220 V, P = 1 kW, |Z| =40 Ω (inductive)a)1000 - j 681.25 VAb)1000 + j 681.25 VAc)681.25 + j1000 VAd)681.25 - j1000 VACorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Determine the complex power for the given values in question.Q. Vrms = 220 V, P = 1 kW, |Z| =40 Ω (inductive)a)1000 - j 681.25 VAb)1000 + j 681.25 VAc)681.25 + j1000 VAd)681.25 - j1000 VACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the complex power for the given values in question.Q. Vrms = 220 V, P = 1 kW, |Z| =40 Ω (inductive)a)1000 - j 681.25 VAb)1000 + j 681.25 VAc)681.25 + j1000 VAd)681.25 - j1000 VACorrect answer is option 'B'. Can you explain this answer?.
Determine the complex power for the given values in question.Q. Vrms = 220 V, P = 1 kW, |Z| =40 Ω (inductive)a)1000 - j 681.25 VAb)1000 + j 681.25 VAc)681.25 + j1000 VAd)681.25 - j1000 VACorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Determine the complex power for the given values in question.Q. Vrms = 220 V, P = 1 kW, |Z| =40 Ω (inductive)a)1000 - j 681.25 VAb)1000 + j 681.25 VAc)681.25 + j1000 VAd)681.25 - j1000 VACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the complex power for the given values in question.Q. Vrms = 220 V, P = 1 kW, |Z| =40 Ω (inductive)a)1000 - j 681.25 VAb)1000 + j 681.25 VAc)681.25 + j1000 VAd)681.25 - j1000 VACorrect answer is option 'B'. Can you explain this answer?.
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