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A parallel plate condenser of capacity 100pF is connected to 230V of AC supply of 300rad/sec frequency. the RMS value of displacement current
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A parallel plate condenser of capacity 100pF is connected to 230V of A...
Introduction
The displacement current is a concept in electromagnetism that was introduced by James Clerk Maxwell to explain certain phenomena that were not accounted for by Ampere's Law. It is an important component of Maxwell's Equations, which describe the behavior of electric and magnetic fields.

Explanation
- Maxwell's Equations: Maxwell's Equations are a set of four fundamental equations that relate electric and magnetic fields to their sources. These equations are:
1. Gauss's Law for Electric Fields
2. Gauss's Law for Magnetic Fields
3. Faraday's Law of Electromagnetic Induction
4. Ampere's Law with Maxwell's Addition

- Ampere's Law: Ampere's Law relates the magnetic field around a closed loop to the electric current passing through the loop. However, Ampere's Law as originally formulated by Ampere did not take into account the changing electric fields.

- Displacement Current: The displacement current is a term introduced by Maxwell to account for the changing electric fields. It is a time-varying electric field that acts like a current and produces a magnetic field. The displacement current is given by the equation:

Id = ε₀(dE/dt)

where Id is the displacement current, ε₀ is the permittivity of free space, and dE/dt is the rate of change of the electric field with respect to time.

- Parallel Plate Capacitor: A parallel plate capacitor consists of two conducting plates separated by a dielectric material. When a potential difference is applied across the plates, an electric field is established between them, and charges accumulate on the plates. The capacitance of the capacitor depends on the area of the plates, the distance between them, and the dielectric constant of the material.

- RMS Value: The RMS (Root Mean Square) value of an AC voltage or current is the value of a steady DC voltage or current that would produce the same amount of power as the AC signal. For a sinusoidal AC signal, the RMS value is given by the peak value divided by the square root of 2.

- Calculation of Displacement Current: In this case, the capacitance of the parallel plate capacitor is given as 100pF. The RMS voltage of the AC supply is 230V, and the angular frequency is 300 rad/sec. The displacement current can be calculated using the formula:

Id = ε₀(dE/dt)

The electric field between the plates of the capacitor is given by:

E = V/d

where V is the voltage across the plates and d is the distance between the plates. Substituting the values, we get:

E = 230V/100pF = 2.3MV/m

Taking the time derivative of the electric field, we get:

dE/dt = 0

Since the voltage is constant in this case, there is no change in the electric field with respect to time, and therefore the displacement current is zero.

Conclusion
In conclusion, the displacement current in a parallel plate capacitor connected to a 230V AC supply with a frequency of 300 rad/sec is zero. This is because the voltage across the plates is
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Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.How shunt is connected with a ammeter?

A parallel plate condenser of capacity 100pF is connected to 230V of AC supply of 300rad/sec frequency. the RMS value of displacement current Related: Maxwell's Equations and Displacement Current?
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