JEE Exam > JEE Questions > An unbiased die with faces marked 1, 2, 3, 4,...
Start Learning for Free
An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)
- a)16 / 81
- b)1 / 81
- c)80 / 81
- d)65 / 81
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four t...
The min. face value is not less than 2 and max. face value is not greater than 5 if we get any of the numbers 2, 3, 4, 5, while total possible out comes are 1, 2 , 3, 4, 5 and 6.
∴ In one thrown of die, prob. of getting any no.
Out of 2, 3, 4 and 5 is
Out of 2, 3, 4 and 5 is
If the die is rolled four times, then all these events being independent, the required prob. 
Free Test
FREE
| Start Free Test |
Community Answer
An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four t...
Probability Calculation for Minimum and Maximum Face Value
To calculate the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, let's break it down into steps:
Step 1: Possible outcomes
- Since the die has faces marked 1 to 6, there are a total of 6 possible outcomes for each roll.
Step 2: Calculating the favorable outcomes
- For the minimum face value to be not less than 2, we can have 5 options (2, 3, 4, 5, 6) for the minimum face value.
- Similarly, for the maximum face value to be not greater than 5, we can have 4 options (2, 3, 4, 5) for the maximum face value.
- The total number of favorable outcomes is the combination of these options, which is 5 * 4 = 20.
Step 3: Calculating the total number of outcomes
- Since the die is rolled four times, the total number of outcomes is 6^4 = 1296.
Step 4: Calculating the probability
- The probability is given by the number of favorable outcomes divided by the total number of outcomes, which is 20 / 1296.
- Simplifying this fraction, we get 5 / 324.
- To make it a more simplified form, we can write it as 1 / 81.
Therefore, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5 is 1 / 81, which corresponds to option 'a'.
To calculate the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, let's break it down into steps:
Step 1: Possible outcomes
- Since the die has faces marked 1 to 6, there are a total of 6 possible outcomes for each roll.
Step 2: Calculating the favorable outcomes
- For the minimum face value to be not less than 2, we can have 5 options (2, 3, 4, 5, 6) for the minimum face value.
- Similarly, for the maximum face value to be not greater than 5, we can have 4 options (2, 3, 4, 5) for the maximum face value.
- The total number of favorable outcomes is the combination of these options, which is 5 * 4 = 20.
Step 3: Calculating the total number of outcomes
- Since the die is rolled four times, the total number of outcomes is 6^4 = 1296.
Step 4: Calculating the probability
- The probability is given by the number of favorable outcomes divided by the total number of outcomes, which is 20 / 1296.
- Simplifying this fraction, we get 5 / 324.
- To make it a more simplified form, we can write it as 1 / 81.
Therefore, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5 is 1 / 81, which corresponds to option 'a'.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer?
Question Description
An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer?.
An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer?.
Solutions for An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer?, a detailed solution for An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is then: (1993 - 1 Mark)a)16 / 81b)1 / 81c)80 / 81d)65 / 81Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup