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Consider a 4 – bit Johnson Counter initialized to ‘0000’. What is the number of clock cycles required for the counter to reset to ‘0000’?
    Correct answer is '8'. Can you explain this answer?
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    Consider a 4 – bit Johnson Counter initialized to ‘0000...
    The Johnson counter resets the input, i.e., reaches the initial input in ‘2n’ clock cycles, where ‘n’ is the number of bits. So, for 4 – bit counter, the counter will reset in 2 X 4 = 8 clock cycles.
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    Consider a 4 – bit Johnson Counter initialized to ‘0000’. What is the number of clock cycles required for the counter to reset to ‘0000’?Correct answer is '8'. Can you explain this answer?
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