Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > Given the vector potential is 16 – 12si...
Start Learning for Free
Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.
- a)28
- b)16
- c)12
- d)4
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Given the vector potential is 16 – 12sin y j. Find the field int...
Answer: c
Explanation: The field intensity is given by H = – Grad(V). The gradient is given by 0 – 12cos y. At the origin, the gradient will be -12 cos 0 = -12. Thus the field intensity will be 12 units.
Explanation: The field intensity is given by H = – Grad(V). The gradient is given by 0 – 12cos y. At the origin, the gradient will be -12 cos 0 = -12. Thus the field intensity will be 12 units.
Most Upvoted Answer
Given the vector potential is 16 – 12sin y j. Find the field int...
Given Vector Potential:
- A = 16 - 12sin(y) j
Field Intensity at Origin:
To find the field intensity at the origin, we need to calculate the curl of the vector potential A.
Curl of Vector Potential:
- Curl(A) = ∇ x A
- Curl(A) = (∂A_z/∂y - ∂A_y/∂z) i + (∂A_x/∂z - ∂A_z/∂x) j + (∂A_y/∂x - ∂A_x/∂y) k
Given A:
- A_x = 16, A_y = -12sin(y), A_z = 0
Calculating Curl(A):
- ∂A_z/∂y = 0, ∂A_y/∂z = 0
- ∂A_x/∂z = 0, ∂A_z/∂x = 0
- ∂A_y/∂x = -12cos(y), ∂A_x/∂y = 0
- Curl(A) = -12cos(y) k
Field Intensity:
- The field intensity is given by the negative gradient of the scalar potential.
Field Intensity at Origin (0,0,0):
- Field Intensity = -∇V(0,0,0)
- Field Intensity = -Curl(A) = 12 k
Answer:
The field intensity at the origin is 12, which corresponds to option 'c'.
- A = 16 - 12sin(y) j
Field Intensity at Origin:
To find the field intensity at the origin, we need to calculate the curl of the vector potential A.
Curl of Vector Potential:
- Curl(A) = ∇ x A
- Curl(A) = (∂A_z/∂y - ∂A_y/∂z) i + (∂A_x/∂z - ∂A_z/∂x) j + (∂A_y/∂x - ∂A_x/∂y) k
Given A:
- A_x = 16, A_y = -12sin(y), A_z = 0
Calculating Curl(A):
- ∂A_z/∂y = 0, ∂A_y/∂z = 0
- ∂A_x/∂z = 0, ∂A_z/∂x = 0
- ∂A_y/∂x = -12cos(y), ∂A_x/∂y = 0
- Curl(A) = -12cos(y) k
Field Intensity:
- The field intensity is given by the negative gradient of the scalar potential.
Field Intensity at Origin (0,0,0):
- Field Intensity = -∇V(0,0,0)
- Field Intensity = -Curl(A) = 12 k
Answer:
The field intensity at the origin is 12, which corresponds to option 'c'.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Top Courses for Electrical Engineering (EE)View all
Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer?
Question Description
Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer?.
Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer?.
Solutions for Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.a)28b)16c)12d)4Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup