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One end of a string of length L is tied to the celling of a lift accelerating upwards with an acceleration 3g. The other end of the string is free. The linear mass density of the string varies linearly from 0 to λ - from bottom to top. Mark out the correct statement for a wave pulse travelling on the string.a)Wave speed is increasing as it travels from bottom to top.b)Acceleration of the wave on the string is uniform.c)Time taken by the pulse to reach from bottom to top will be √2L/g .d)All of the aboveCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One end of a string of length L is tied to the celling of a lift accelerating upwards with an acceleration 3g. The other end of the string is free. The linear mass density of the string varies linearly from 0 to λ - from bottom to top. Mark out the correct statement for a wave pulse travelling on the string.a)Wave speed is increasing as it travels from bottom to top.b)Acceleration of the wave on the string is uniform.c)Time taken by the pulse to reach from bottom to top will be √2L/g .d)All of the aboveCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One end of a string of length L is tied to the celling of a lift accelerating upwards with an acceleration 3g. The other end of the string is free. The linear mass density of the string varies linearly from 0 to λ - from bottom to top. Mark out the correct statement for a wave pulse travelling on the string.a)Wave speed is increasing as it travels from bottom to top.b)Acceleration of the wave on the string is uniform.c)Time taken by the pulse to reach from bottom to top will be √2L/g .d)All of the aboveCorrect answer is option 'D'. Can you explain this answer?.

Solutions for One end of a string of length L is tied to the celling of a lift accelerating upwards with an acceleration 3g. The other end of the string is free. The linear mass density of the string varies linearly from 0 to λ - from bottom to top. Mark out the correct statement for a wave pulse travelling on the string.a)Wave speed is increasing as it travels from bottom to top.b)Acceleration of the wave on the string is uniform.c)Time taken by the pulse to reach from bottom to top will be √2L/g .d)All of the aboveCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of One end of a string of length L is tied to the celling of a lift accelerating upwards with an acceleration 3g. The other end of the string is free. The linear mass density of the string varies linearly from 0 to λ - from bottom to top. Mark out the correct statement for a wave pulse travelling on the string.a)Wave speed is increasing as it travels from bottom to top.b)Acceleration of the wave on the string is uniform.c)Time taken by the pulse to reach from bottom to top will be √2L/g .d)All of the aboveCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of One end of a string of length L is tied to the celling of a lift accelerating upwards with an acceleration 3g. The other end of the string is free. The linear mass density of the string varies linearly from 0 to λ - from bottom to top. Mark out the correct statement for a wave pulse travelling on the string.a)Wave speed is increasing as it travels from bottom to top.b)Acceleration of the wave on the string is uniform.c)Time taken by the pulse to reach from bottom to top will be √2L/g .d)All of the aboveCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for One end of a string of length L is tied to the celling of a lift accelerating upwards with an acceleration 3g. The other end of the string is free. The linear mass density of the string varies linearly from 0 to λ - from bottom to top. Mark out the correct statement for a wave pulse travelling on the string.a)Wave speed is increasing as it travels from bottom to top.b)Acceleration of the wave on the string is uniform.c)Time taken by the pulse to reach from bottom to top will be √2L/g .d)All of the aboveCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of One end of a string of length L is tied to the celling of a lift accelerating upwards with an acceleration 3g. The other end of the string is free. The linear mass density of the string varies linearly from 0 to λ - from bottom to top. Mark out the correct statement for a wave pulse travelling on the string.a)Wave speed is increasing as it travels from bottom to top.b)Acceleration of the wave on the string is uniform.c)Time taken by the pulse to reach from bottom to top will be √2L/g .d)All of the aboveCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice One end of a string of length L is tied to the celling of a lift accelerating upwards with an acceleration 3g. The other end of the string is free. The linear mass density of the string varies linearly from 0 to λ - from bottom to top. Mark out the correct statement for a wave pulse travelling on the string.a)Wave speed is increasing as it travels from bottom to top.b)Acceleration of the wave on the string is uniform.c)Time taken by the pulse to reach from bottom to top will be √2L/g .d)All of the aboveCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.