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Find the magnetic field intensity when the current density is 0.5 units for an area up to 20 units.
- a)10
- b)5
- c)20
- d)40
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Find the magnetic field intensity when the current density is 0.5 unit...
Answer: a
Explanation: We know that ∫ H.dl = I. By Stoke’s law, we can write Curl(H) = J. In integral form, H = ∫ J.ds, where J = 0.5 and ds is defined by 20 units. Thus H = 0.5 x 20 = 10 units.
Explanation: We know that ∫ H.dl = I. By Stoke’s law, we can write Curl(H) = J. In integral form, H = ∫ J.ds, where J = 0.5 and ds is defined by 20 units. Thus H = 0.5 x 20 = 10 units.
Most Upvoted Answer
Find the magnetic field intensity when the current density is 0.5 unit...
Magnetic Field Intensity Calculation
The magnetic field intensity (H) can be calculated using the formula:
H = (J x d) / μ
Where:
- J is the current density
- d is the distance from the current
- μ is the permeability of the medium
In this case, the current density is given as 0.5 units and the area up to which the magnetic field intensity is to be calculated is 20 units.
Given:
Current density (J) = 0.5 units
Distance (d) = 20 units
To calculate the magnetic field intensity, we need to know the permeability of the medium. The permeability depends on the material through which the current is passing.
Let's assume that the medium is air, which has a permeability of μ0 = 4π x 10^-7 T.m/A. Using this value, we can calculate the magnetic field intensity.
Calculations:
μ = μ0 = 4π x 10^-7 T.m/A
J = 0.5 units
d = 20 units
Substituting the values into the formula:
H = (J x d) / μ
= (0.5 x 20) / (4π x 10^-7)
= 10 / (4π x 10^-7)
≈ 795.77 A/m
Therefore, the magnetic field intensity is approximately 795.77 A/m.
Conclusion:
The magnetic field intensity when the current density is 0.5 units for an area up to 20 units is approximately 795.77 A/m. None of the provided answer options (a) 10, (b) 5, (c) 20, (d) 40) match the correct answer.
The magnetic field intensity (H) can be calculated using the formula:
H = (J x d) / μ
Where:
- J is the current density
- d is the distance from the current
- μ is the permeability of the medium
In this case, the current density is given as 0.5 units and the area up to which the magnetic field intensity is to be calculated is 20 units.
Given:
Current density (J) = 0.5 units
Distance (d) = 20 units
To calculate the magnetic field intensity, we need to know the permeability of the medium. The permeability depends on the material through which the current is passing.
Let's assume that the medium is air, which has a permeability of μ0 = 4π x 10^-7 T.m/A. Using this value, we can calculate the magnetic field intensity.
Calculations:
μ = μ0 = 4π x 10^-7 T.m/A
J = 0.5 units
d = 20 units
Substituting the values into the formula:
H = (J x d) / μ
= (0.5 x 20) / (4π x 10^-7)
= 10 / (4π x 10^-7)
≈ 795.77 A/m
Therefore, the magnetic field intensity is approximately 795.77 A/m.
Conclusion:
The magnetic field intensity when the current density is 0.5 units for an area up to 20 units is approximately 795.77 A/m. None of the provided answer options (a) 10, (b) 5, (c) 20, (d) 40) match the correct answer.
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