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Common data for 12 & 13
A commercial refrigerator is used to keep the refrigerated space at -300C by rejecting its waste heat to cooling water. This cooling water enters the condenser at 180C (hw = 75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94 kJ/kg). The refrigerant enters the condenser at 1.2 MPa, 650C (h = 295.16 kJ/kg) and leaves at 420C (h = 111.23 kJ/kg). The inlet state of the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and the compressor is estimated to gain a net heat of 450W from the surroundings:
Q. The refrigeration load will be
- a)9.13 kW
- b)5.85 kW
- c)4.39 kW
- d)7.31 kW
Correct answer is option 'B'. Can you explain this answer?
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Common data for 12 could include:
1. The number 12 is an even number.
2. It is the product of 3 and 4.
3. It is a highly composite number, meaning it has more divisors than any smaller natural number.
4. In a 12-hour clock system, it represents the number of hours in a half day.
5. It is the number of months in a year.
6. In many cultures, 12 is considered a symbol of completeness and perfection.
7. It is the atomic number of the element magnesium.
8. 12 is a number often associated with groups and sets, such as a dozen or a gross.
9. It is the highest single-digit number in the duodecimal numeral system.
10. In mathematics, 12 is a highly abundant number.
11. It is the number of days in Christmas celebrations, known as the Twelve Days of Christmas.
12. 12 is the number of edges in a cube.
1. The number 12 is an even number.
2. It is the product of 3 and 4.
3. It is a highly composite number, meaning it has more divisors than any smaller natural number.
4. In a 12-hour clock system, it represents the number of hours in a half day.
5. It is the number of months in a year.
6. In many cultures, 12 is considered a symbol of completeness and perfection.
7. It is the atomic number of the element magnesium.
8. 12 is a number often associated with groups and sets, such as a dozen or a gross.
9. It is the highest single-digit number in the duodecimal numeral system.
10. In mathematics, 12 is a highly abundant number.
11. It is the number of days in Christmas celebrations, known as the Twelve Days of Christmas.
12. 12 is the number of edges in a cube.
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Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer?
Question Description
Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer?.
Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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Here you can find the meaning of Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Common data for 12 & 13A commercial refrigerator is usedto keep the refrigerated space at-300C by rejecting its waste heat tocooling water. This cooling waterenters the condenser at 180C (hw =75.47 kJ/kg) with a rate of 0.25 kg/s and leaves at 260C (hw = 108.94kJ/kg). The refrigerant enters thecondenser at 1.2 MPa, 650C (h =295.16 kJ/kg) and leaves at 420C(h = 111.23 kJ/kg). The inlet stateof the compressor is 60 kPa, -340C (h = 230.03 kJ/kg) and thecompressor is estimated to gain anet heat of 450W from thesurroundings:Q. The refrigeration load will bea)9.13 kWb)5.85 kWc)4.39 kWd)7.31 kWCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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