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A 2 g block attached to an ideal spring with spring constant 80 N/m oscillates on a horizontal friction less surface. When the spring is 4 cm shorter than its equilibrium length, the speed of block is root 17 m/s. The greatest speed of the the block is ?
Most Upvoted Answer
A 2 g block attached to an ideal spring with spring constant 80 N/m os...
Given Information:
- Mass of block = 2 g = 0.002 kg
- Spring constant = 80 N/m
- Compression of spring = 4 cm = 0.04 m
- Speed of block at compression = $\sqrt{17}$ m/s
Calculation:
Find the amplitude of motion:
- Using the formula for the energy of a simple harmonic oscillator, we have:
- $\frac{1}{2}kA^2 = \frac{1}{2}mv^2$
- where k is the spring constant, A is the amplitude of motion, m is the mass of the block, and v is the speed of the block
- Substituting the given values, we get:
- $\frac{1}{2}(80)(A^2) = \frac{1}{2}(0.002)(\sqrt{17})^2$
- $A = 0.05$ m
Find the maximum speed of the block:
- Using the formula for the maximum speed of a simple harmonic oscillator, we have:
- $v_{max} = A\sqrt{k/m}$
- Substituting the given values, we get:
- $v_{max} = 0.05\sqrt{\frac{80}{0.002}}$
- $v_{max} = 20$ m/s
Answer:
- The greatest speed of the block is 20 m/s.
Community Answer
A 2 g block attached to an ideal spring with spring constant 80 N/m os...
Work done by spring force = ∆K.E
1/2(k)x^2=1/2m(v^2-u^2)
1/2(80) (0.04) ^2=1/2(0.002) (v^2-(√17) ^)
after solving we get v=9m/s
1/2(k)x^2=1/2m(v^2-u^2)
1/2(80) (0.04) ^2=1/2(0.002) (v^2-(√17) ^)
after solving we get v=9m/s
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A 2 g block attached to an ideal spring with spring constant 80 N/m oscillates on a horizontal friction less surface. When the spring is 4 cm shorter than its equilibrium length, the speed of block is root 17 m/s. The greatest speed of the the block is ?
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A 2 g block attached to an ideal spring with spring constant 80 N/m oscillates on a horizontal friction less surface. When the spring is 4 cm shorter than its equilibrium length, the speed of block is root 17 m/s. The greatest speed of the the block is ? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 2 g block attached to an ideal spring with spring constant 80 N/m oscillates on a horizontal friction less surface. When the spring is 4 cm shorter than its equilibrium length, the speed of block is root 17 m/s. The greatest speed of the the block is ? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 2 g block attached to an ideal spring with spring constant 80 N/m oscillates on a horizontal friction less surface. When the spring is 4 cm shorter than its equilibrium length, the speed of block is root 17 m/s. The greatest speed of the the block is ?.
A 2 g block attached to an ideal spring with spring constant 80 N/m oscillates on a horizontal friction less surface. When the spring is 4 cm shorter than its equilibrium length, the speed of block is root 17 m/s. The greatest speed of the the block is ? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 2 g block attached to an ideal spring with spring constant 80 N/m oscillates on a horizontal friction less surface. When the spring is 4 cm shorter than its equilibrium length, the speed of block is root 17 m/s. The greatest speed of the the block is ? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 2 g block attached to an ideal spring with spring constant 80 N/m oscillates on a horizontal friction less surface. When the spring is 4 cm shorter than its equilibrium length, the speed of block is root 17 m/s. The greatest speed of the the block is ?.
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