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a moving Coil galvanometer allows a full scale current 10-4 A.A series resistance of2-M Ω is required  to convert the above galvanometer  into a voltmeter of range 0-5V.Therefore the value of shunt resistance  required to convert the above galvanometer in to ammeter of range 0-10mA is :
  • a)
    100 Ω
  • b)
    10 Ω
  • c)
    500 Ω
  • d)
    200 Ω
Correct answer is option 'D'. Can you explain this answer?
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Calculation of Shunt Resistance for Ammeter Conversion:

Given:
Full scale current of moving coil galvanometer = 10^-4 A
Series resistance for voltmeter conversion = 2 MΩ
Voltmeter range = 0-5V
Desired ammeter range = 0-10mA

Calculations:
1. Calculate the resistance required for voltmeter conversion:
Voltage range = 5V
Current range = 10^-4 A
Series resistance for voltmeter = 2 MΩ
Using Ohm's Law: R = V/I
R = 5V / 10^-4 A = 50 kΩ
Total resistance for voltmeter = 50 kΩ + 2 MΩ = 2.05 MΩ
2. Calculate the shunt resistance for ammeter conversion:
Desired current range = 10 mA = 10^-2 A
Current through galvanometer = Full scale current - Desired current
= 10^-4 A - 10^-2 A = -10^-2 A (opposite direction)
Shunt resistance = Total resistance / (Desired current / Full scale current)
Shunt resistance = 2.05 MΩ / (10^-2 A / 10^-4 A) = 0.205 Ω = 200 Ω
Therefore, the shunt resistance required to convert the galvanometer into an ammeter of range 0-10mA is 200 Ω.
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a moving Coil galvanometer allows a full scale current 10-4 A.A series resistance of2-M Ωis required to convert the above galvanometer into a voltmeter of range 0-5V.Therefore the value of shunt resistance required to convert the above galvanometer in to ammeter of range 0-10mA is :a)100Ωb)10Ωc)500Ωd)200ΩCorrect answer is option 'D'. Can you explain this answer?
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