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Two mutually perpendicular straight lines through the origin form an isosceles triangle with the line 2x y=5. Then area of the triangle?
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Two mutually perpendicular straight lines through the origin form an i...
Solution:


Given:

- Two mutually perpendicular straight lines through the origin form an isosceles triangle with the line 2x y=5.

To find:

- The area of the triangle.

Approach:

- Let the two perpendicular lines be y = mx and x = my.
- Let P and Q be the points of intersection of the two lines.
- Let R be the point of intersection of the line 2x y=5 and the line y = mx.

Calculation:

- Since the two perpendicular lines are isosceles, the distance from the origin to P and Q is equal.
- Therefore, OP = OQ.
- Using the distance formula, we get (m^2 + 1)^(1/2) |PQ| = 2 |PR|.
- Also, PR = (2/ (m^2 + 1)^(1/2)) (5 / (2^2 + m^2)^(1/2)).
- The area of the triangle can be found as (1/2) |PQ| |PR|.
- On substituting the values of |PQ| and |PR|, we get the area of the triangle as 5 / 2.

Answer:

- Therefore, the area of the triangle is 5 / 2.
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Two mutually perpendicular straight lines through the origin form an isosceles triangle with the line 2x y=5. Then area of the triangle?
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