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A beam of light consisting of two wavelengths 6500 Å and 5200 Å is used to obtain interference fringes in Young's double slit experiment. The distance between slits is 2mm and the distance of screen from slits is 120 cm. What is the least distance from central maximum where the bright due to both wavelength coincide ?
- a)0.156 cm
- b)0.312 cm
- c)0.078 cm
- d)0.468 cm
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A beam of light consisting of two wavelengths 6500 Å and 5200 &A...
If n is least number of fringes of λ1(=6500A∘) which are coincident with (n+1) of smaller wavelength
also β=λD/d
substituting values for wavelength,D and d we get β = 0.039cm
So,
Hence b is the correct answer.
also β=λD/d
substituting values for wavelength,D and d we get β = 0.039cm
So,
Hence b is the correct answer.
Most Upvoted Answer
A beam of light consisting of two wavelengths 6500 Å and 5200 &A...
And 5500 Angstroms is incident on a diffraction grating. The angle between the first-order maxima for these two wavelengths is 30 degrees. What is the spacing between the lines of the grating?
To solve this problem, we can use the equation for the diffraction grating:
nλ = d sin(θ)
where n is the order of the maximum, λ is the wavelength of light, d is the spacing between the lines of the grating, and θ is the angle between the incident beam and the first-order maximum.
For the first wavelength (6500 Angstroms), we have:
1 * 6500 = d sin(30 degrees)
For the second wavelength (5500 Angstroms), we have:
1 * 5500 = d sin(30 degrees)
Dividing the two equations, we get:
6500 / 5500 = (d sin(30 degrees)) / (d sin(30 degrees))
Simplifying, we find:
1.18 = 1
This is not possible, so there must be an error in the problem statement or calculations. Please double-check the given information and try again.
To solve this problem, we can use the equation for the diffraction grating:
nλ = d sin(θ)
where n is the order of the maximum, λ is the wavelength of light, d is the spacing between the lines of the grating, and θ is the angle between the incident beam and the first-order maximum.
For the first wavelength (6500 Angstroms), we have:
1 * 6500 = d sin(30 degrees)
For the second wavelength (5500 Angstroms), we have:
1 * 5500 = d sin(30 degrees)
Dividing the two equations, we get:
6500 / 5500 = (d sin(30 degrees)) / (d sin(30 degrees))
Simplifying, we find:
1.18 = 1
This is not possible, so there must be an error in the problem statement or calculations. Please double-check the given information and try again.
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Community Answer
A beam of light consisting of two wavelengths 6500 Å and 5200 &A...
Option A is correct
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A beam of light consisting of two wavelengths 6500 Å and 5200 Å is used to obtain interference fringes in Young's double slit experiment. The distance between slits is 2mm and the distance of screen from slits is 120 cm. What is the least distance from central maximum where the bright due to both wavelength coincide ?a)0.156 cmb)0.312 cmc)0.078 cmd)0.468 cmCorrect answer is option 'A'. Can you explain this answer?
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A beam of light consisting of two wavelengths 6500 Å and 5200 Å is used to obtain interference fringes in Young's double slit experiment. The distance between slits is 2mm and the distance of screen from slits is 120 cm. What is the least distance from central maximum where the bright due to both wavelength coincide ?a)0.156 cmb)0.312 cmc)0.078 cmd)0.468 cmCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A beam of light consisting of two wavelengths 6500 Å and 5200 Å is used to obtain interference fringes in Young's double slit experiment. The distance between slits is 2mm and the distance of screen from slits is 120 cm. What is the least distance from central maximum where the bright due to both wavelength coincide ?a)0.156 cmb)0.312 cmc)0.078 cmd)0.468 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beam of light consisting of two wavelengths 6500 Å and 5200 Å is used to obtain interference fringes in Young's double slit experiment. The distance between slits is 2mm and the distance of screen from slits is 120 cm. What is the least distance from central maximum where the bright due to both wavelength coincide ?a)0.156 cmb)0.312 cmc)0.078 cmd)0.468 cmCorrect answer is option 'A'. Can you explain this answer?.
A beam of light consisting of two wavelengths 6500 Å and 5200 Å is used to obtain interference fringes in Young's double slit experiment. The distance between slits is 2mm and the distance of screen from slits is 120 cm. What is the least distance from central maximum where the bright due to both wavelength coincide ?a)0.156 cmb)0.312 cmc)0.078 cmd)0.468 cmCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A beam of light consisting of two wavelengths 6500 Å and 5200 Å is used to obtain interference fringes in Young's double slit experiment. The distance between slits is 2mm and the distance of screen from slits is 120 cm. What is the least distance from central maximum where the bright due to both wavelength coincide ?a)0.156 cmb)0.312 cmc)0.078 cmd)0.468 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beam of light consisting of two wavelengths 6500 Å and 5200 Å is used to obtain interference fringes in Young's double slit experiment. The distance between slits is 2mm and the distance of screen from slits is 120 cm. What is the least distance from central maximum where the bright due to both wavelength coincide ?a)0.156 cmb)0.312 cmc)0.078 cmd)0.468 cmCorrect answer is option 'A'. Can you explain this answer?.
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