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The graph of the linear equation 4x 3y = 12 cuts the x-axis at the point?
Verified Answer
The graph of the linear equation 4x 3y = 12 cuts the x-axis at the po...
4x + 3y = 12
⇒ 3y = 12 – 4x







The blue line in the graph is the required line of the equation, 4x + 3y = 12
According to the graph, the equation,
4x + 3y = 12 cuts the x-axis at the point (3, 0)
This question is part of UPSC exam. View all Class 9 courses
Most Upvoted Answer
The graph of the linear equation 4x 3y = 12 cuts the x-axis at the po...
The Linear Equation
The given linear equation is 4x - 3y = 12.

Finding the x-intercept
To find the point where the graph of the equation cuts the x-axis, we need to determine the value of x when y is equal to zero.

Substituting y = 0
Let's substitute y = 0 into the equation and solve for x:

4x - 3(0) = 12
4x = 12
x = 12/4
x = 3

The x-intercept
The x-intercept is the point where the graph crosses or intersects the x-axis. In this case, the x-intercept is (3, 0).

Graphical representation
To visually represent the graph of the equation, we can plot the x-intercept (3, 0) on a coordinate plane.

Explanation
When the value of y is zero, the equation becomes 4x - 3(0) = 12, which simplifies to 4x = 12. Solving for x, we find that x = 3. Therefore, the graph of the equation cuts the x-axis at the point (3, 0).

Visually appealing answer:

The linear equation 4x - 3y = 12 cuts the x-axis at the point (3, 0). This is determined by substituting y = 0 into the equation and solving for x. The x-intercept is the point where the graph crosses or intersects the x-axis. In this case, the x-intercept is (3, 0).
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The graph of the linear equation 4x 3y = 12 cuts the x-axis at the point?
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