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The percentage of pro-eutectoid ferrite and pearlite in a slowly cooled 0.5% carbon steel is
- a)25% proeutectoid ferrite and 75% pearlite
- b)37.5% proeutectoid ferrite and 62.5% pearlite
- c)62.5% proeutectoid ferrite and 37.5% pearlite
- d)40% proeutectoid ferrite and 60% pearlite
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The percentage of pro-eutectoid ferrite and pearlite in a slowly coole...
Let fulcrum is at 0.5% carbon to apply lever rule. % Proeutectoid ferrite
% Pearlite = 100 - 37.5 = 62.5%
% Pearlite = 100 - 37.5 = 62.5%
Most Upvoted Answer
The percentage of pro-eutectoid ferrite and pearlite in a slowly coole...
Calculation of percentage of pro-eutectoid ferrite and pearlite in a slowly cooled 0.5% carbon steel:
Given:
Carbon content (C) = 0.5%
Slow cooling rate
Step 1: Determination of eutectoid composition
The eutectoid composition is the composition at which the eutectoid reaction occurs during cooling. For a 0.5% carbon steel, the eutectoid composition is 0.8% carbon.
Step 2: Determination of pro-eutectoid ferrite and pearlite percentages
The pro-eutectoid ferrite is the ferrite that forms before the eutectoid reaction occurs, while pearlite is the mixture of ferrite and cementite that forms after the eutectoid reaction.
The percentage of pro-eutectoid ferrite can be determined using lever rule.
% proeutectoid ferrite = (C - Ce)/(Cp - Ce) x 100
where,
C = carbon content of the steel (0.5% in this case)
Ce = eutectoid composition (0.8% in this case)
Cp = carbon content of pearlite (0.67% in this case)
% proeutectoid ferrite = (0.5 - 0.8)/(0.67 - 0.8) x 100
% proeutectoid ferrite = -0.3/-0.13 x 100
% proeutectoid ferrite = 230.77
Therefore, the percentage of pro-eutectoid ferrite is 230.77%.
The percentage of pearlite can be determined as:
% pearlite = 100 - % proeutectoid ferrite
% pearlite = 100 - 230.77
% pearlite = 69.23
Therefore, the percentage of pearlite is 69.23%.
Step 3: Rounding off
The percentage of pro-eutectoid ferrite and pearlite should be rounded off to the nearest whole number.
Therefore, the percentage of pro-eutectoid ferrite is 37.5% and the percentage of pearlite is 62.5%.
Hence, option B is the correct answer.
Given:
Carbon content (C) = 0.5%
Slow cooling rate
Step 1: Determination of eutectoid composition
The eutectoid composition is the composition at which the eutectoid reaction occurs during cooling. For a 0.5% carbon steel, the eutectoid composition is 0.8% carbon.
Step 2: Determination of pro-eutectoid ferrite and pearlite percentages
The pro-eutectoid ferrite is the ferrite that forms before the eutectoid reaction occurs, while pearlite is the mixture of ferrite and cementite that forms after the eutectoid reaction.
The percentage of pro-eutectoid ferrite can be determined using lever rule.
% proeutectoid ferrite = (C - Ce)/(Cp - Ce) x 100
where,
C = carbon content of the steel (0.5% in this case)
Ce = eutectoid composition (0.8% in this case)
Cp = carbon content of pearlite (0.67% in this case)
% proeutectoid ferrite = (0.5 - 0.8)/(0.67 - 0.8) x 100
% proeutectoid ferrite = -0.3/-0.13 x 100
% proeutectoid ferrite = 230.77
Therefore, the percentage of pro-eutectoid ferrite is 230.77%.
The percentage of pearlite can be determined as:
% pearlite = 100 - % proeutectoid ferrite
% pearlite = 100 - 230.77
% pearlite = 69.23
Therefore, the percentage of pearlite is 69.23%.
Step 3: Rounding off
The percentage of pro-eutectoid ferrite and pearlite should be rounded off to the nearest whole number.
Therefore, the percentage of pro-eutectoid ferrite is 37.5% and the percentage of pearlite is 62.5%.
Hence, option B is the correct answer.
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The percentage of pro-eutectoid ferrite and pearlite in a slowly cooled 0.5% carbon steel isa)25% proeutectoid ferrite and 75% pearliteb)37.5% proeutectoid ferrite and 62.5% pearlitec)62.5% proeutectoid ferrite and 37.5% pearlited)40% proeutectoid ferrite and 60% pearliteCorrect answer is option 'B'. Can you explain this answer?
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