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A moving coil instrument has the following data:
Number of turns = 100
Width of the coii = 20 mm
Depth of the coil = 30 mm
Flux density in the gap = 0.1 Wb/m2
If the control spring constant is 2 x 10-6 N-m/ degree, then the deflection of the pointer when the coil carries a current of 10 mA is
Number of turns = 100
Width of the coii = 20 mm
Depth of the coil = 30 mm
Flux density in the gap = 0.1 Wb/m2
If the control spring constant is 2 x 10-6 N-m/ degree, then the deflection of the pointer when the coil carries a current of 10 mA is
- a)π/3 radians
- b)π/2 radians
- c)π/6 radians
- d)π/4 radians
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A moving coil instrument has the following data:Number of turns = 100W...
The deflecting torque,
At equilibrium,
Tc = Td
Thus, the deflection of the pointer = π/6 radian.
At equilibrium,
Tc = Td
Thus, the deflection of the pointer = π/6 radian.
Most Upvoted Answer
A moving coil instrument has the following data:Number of turns = 100W...
We can use the formula for the torque on a moving coil instrument:
T = nABIsinθ
where:
- T is the torque on the coil
- n is the number of turns
- A is the area of the coil (width times depth)
- B is the flux density in the gap
- I is the current in the coil
- θ is the angle between the magnetic field and the plane of the coil
The torque is balanced by the torque from the control spring, which is given by:
T = kθ
where k is the control spring constant and θ is the deflection angle of the pointer.
At equilibrium, these two torques are equal, so we can set them equal to each other:
nABIsinθ = kθ
We can rearrange this to solve for θ:
θ = (nABIsinθ) / k
Plugging in the given values, we get:
n = 100
A = 20 mm x 30 mm = 600 mm2 = 0.0006 m2
B = 0.1 Wb/m2
I = 10 mA = 0.01 A
k = 2 x 10-6 N-m/ degree
θ = (100 x 0.0006 m2 x 0.1 Wb/m2 x 0.01 A x sinθ) / (2 x 10-6 N-m/ degree)
Simplifying and solving for θ, we get:
θ = 0.03 sinθ degrees
Therefore, the deflection of the pointer when the coil carries a current of 10 mA is approximately 0.03 times the sine of the angle between the magnetic field and the plane of the coil. The actual angle would depend on the geometry of the instrument and the strength and alignment of the magnetic field.
T = nABIsinθ
where:
- T is the torque on the coil
- n is the number of turns
- A is the area of the coil (width times depth)
- B is the flux density in the gap
- I is the current in the coil
- θ is the angle between the magnetic field and the plane of the coil
The torque is balanced by the torque from the control spring, which is given by:
T = kθ
where k is the control spring constant and θ is the deflection angle of the pointer.
At equilibrium, these two torques are equal, so we can set them equal to each other:
nABIsinθ = kθ
We can rearrange this to solve for θ:
θ = (nABIsinθ) / k
Plugging in the given values, we get:
n = 100
A = 20 mm x 30 mm = 600 mm2 = 0.0006 m2
B = 0.1 Wb/m2
I = 10 mA = 0.01 A
k = 2 x 10-6 N-m/ degree
θ = (100 x 0.0006 m2 x 0.1 Wb/m2 x 0.01 A x sinθ) / (2 x 10-6 N-m/ degree)
Simplifying and solving for θ, we get:
θ = 0.03 sinθ degrees
Therefore, the deflection of the pointer when the coil carries a current of 10 mA is approximately 0.03 times the sine of the angle between the magnetic field and the plane of the coil. The actual angle would depend on the geometry of the instrument and the strength and alignment of the magnetic field.
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A moving coil instrument has the following data:Number of turns = 100Width of the coii = 20 mmDepth of the coil = 30 mmFlux density in the gap = 0.1 Wb/m2If the control spring constant is 2 x 10-6 N-m/ degree, then the deflection of the pointer when the coil carries a current of 10 mA isa)π/3radiansb)π/2radiansc)π/6radiansd)π/4radiansCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A moving coil instrument has the following data:Number of turns = 100Width of the coii = 20 mmDepth of the coil = 30 mmFlux density in the gap = 0.1 Wb/m2If the control spring constant is 2 x 10-6 N-m/ degree, then the deflection of the pointer when the coil carries a current of 10 mA isa)π/3radiansb)π/2radiansc)π/6radiansd)π/4radiansCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A moving coil instrument has the following data:Number of turns = 100Width of the coii = 20 mmDepth of the coil = 30 mmFlux density in the gap = 0.1 Wb/m2If the control spring constant is 2 x 10-6 N-m/ degree, then the deflection of the pointer when the coil carries a current of 10 mA isa)π/3radiansb)π/2radiansc)π/6radiansd)π/4radiansCorrect answer is option 'C'. Can you explain this answer?.
A moving coil instrument has the following data:Number of turns = 100Width of the coii = 20 mmDepth of the coil = 30 mmFlux density in the gap = 0.1 Wb/m2If the control spring constant is 2 x 10-6 N-m/ degree, then the deflection of the pointer when the coil carries a current of 10 mA isa)π/3radiansb)π/2radiansc)π/6radiansd)π/4radiansCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A moving coil instrument has the following data:Number of turns = 100Width of the coii = 20 mmDepth of the coil = 30 mmFlux density in the gap = 0.1 Wb/m2If the control spring constant is 2 x 10-6 N-m/ degree, then the deflection of the pointer when the coil carries a current of 10 mA isa)π/3radiansb)π/2radiansc)π/6radiansd)π/4radiansCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A moving coil instrument has the following data:Number of turns = 100Width of the coii = 20 mmDepth of the coil = 30 mmFlux density in the gap = 0.1 Wb/m2If the control spring constant is 2 x 10-6 N-m/ degree, then the deflection of the pointer when the coil carries a current of 10 mA isa)π/3radiansb)π/2radiansc)π/6radiansd)π/4radiansCorrect answer is option 'C'. Can you explain this answer?.
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