Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Questions > Three message signals each band limited to 10...
Start Learning for Free
Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel is
- a)49 kHz
- b)45 kHz
- c)53 kHz
- d)57 kHz
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz a...
BW after AM modulation = 2 x 10 = 20 KHz
BW after DSS-SC modulation = 2 x10 = 20 KHz BW after SSB modulation = 5 KHz
Guard band width = 2 x 2k=4 k
∴ Total BW after frequency multiplexing = 49 KHz
Most Upvoted Answer
Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz a...
Solution:
Given:
Bandwidth of the first message signal = 10 kHz
Bandwidth of the second message signal = 10 kHz
Bandwidth of the third message signal = 5 kHz
Guard band = 2 kHz
Modulation used for the first message signal = Any modulation
Modulation used for the second message signal = D513-SC
Modulation used for the third message signal = SSB
To find: Bandwidth of the channel
Frequency Division Multiplexing (FDM):
FDM is a technique of combining multiple signals and transmitting them over a single channel. In FDM, each message signal is modulated with a carrier signal of different frequencies. The modulated signals are then combined and transmitted over a single channel.
The given system uses FDM to transmit three message signals.
Bandwidth Calculation:
The bandwidth of the channel is given by the sum of the bandwidths of all the modulated signals and the guard band.
Bandwidth of the first modulated signal:
As the modulation used for the first message signal is any modulation, we assume that it is modulated using AM (Amplitude Modulation).
The bandwidth of AM is given by the formula,
BAM = 2 × (fm + fc)
where,
fm = Maximum frequency component of the message signal
fc = Carrier frequency
Here, fc = 0 Hz (baseband signal)
fm = 10 kHz (Given)
BAM = 2 × (10 kHz + 0 Hz) = 20 kHz
Bandwidth of the second modulated signal:
The modulation used for the second message signal is D513-SC (Double Sideband with 5 kHz carrier).
The bandwidth of D513-SC is given by the formula,
BD513-SC = 2 × (fm + fc)
where,
fm = Maximum frequency component of the message signal
fc = Carrier frequency
Here, fc = 5 kHz (Given)
fm = 10 kHz (Given)
BD513-SC = 2 × (10 kHz + 5 kHz) = 30 kHz
Bandwidth of the third modulated signal:
The modulation used for the third message signal is SSB (Single Sideband).
The bandwidth of SSB is equal to the bandwidth of the message signal.
Here, the maximum frequency component of the message signal is 5 kHz.
Bandwidth of SSB = 5 kHz
Total bandwidth of the modulated signals:
Total bandwidth of the modulated signals = BAM + BD513-SC + Bandwidth of SSB
= 20 kHz + 30 kHz + 5 kHz
= 55 kHz
Total bandwidth of the channel:
Total bandwidth of the channel = Total bandwidth of the modulated signals + Guard band
= 55 kHz + 2 kHz
= 57 kHz
Therefore, the bandwidth of the channel is 57 kHz.
Hence, option (D) is the correct answer.
Given:
Bandwidth of the first message signal = 10 kHz
Bandwidth of the second message signal = 10 kHz
Bandwidth of the third message signal = 5 kHz
Guard band = 2 kHz
Modulation used for the first message signal = Any modulation
Modulation used for the second message signal = D513-SC
Modulation used for the third message signal = SSB
To find: Bandwidth of the channel
Frequency Division Multiplexing (FDM):
FDM is a technique of combining multiple signals and transmitting them over a single channel. In FDM, each message signal is modulated with a carrier signal of different frequencies. The modulated signals are then combined and transmitted over a single channel.
The given system uses FDM to transmit three message signals.
Bandwidth Calculation:
The bandwidth of the channel is given by the sum of the bandwidths of all the modulated signals and the guard band.
Bandwidth of the first modulated signal:
As the modulation used for the first message signal is any modulation, we assume that it is modulated using AM (Amplitude Modulation).
The bandwidth of AM is given by the formula,
BAM = 2 × (fm + fc)
where,
fm = Maximum frequency component of the message signal
fc = Carrier frequency
Here, fc = 0 Hz (baseband signal)
fm = 10 kHz (Given)
BAM = 2 × (10 kHz + 0 Hz) = 20 kHz
Bandwidth of the second modulated signal:
The modulation used for the second message signal is D513-SC (Double Sideband with 5 kHz carrier).
The bandwidth of D513-SC is given by the formula,
BD513-SC = 2 × (fm + fc)
where,
fm = Maximum frequency component of the message signal
fc = Carrier frequency
Here, fc = 5 kHz (Given)
fm = 10 kHz (Given)
BD513-SC = 2 × (10 kHz + 5 kHz) = 30 kHz
Bandwidth of the third modulated signal:
The modulation used for the third message signal is SSB (Single Sideband).
The bandwidth of SSB is equal to the bandwidth of the message signal.
Here, the maximum frequency component of the message signal is 5 kHz.
Bandwidth of SSB = 5 kHz
Total bandwidth of the modulated signals:
Total bandwidth of the modulated signals = BAM + BD513-SC + Bandwidth of SSB
= 20 kHz + 30 kHz + 5 kHz
= 55 kHz
Total bandwidth of the channel:
Total bandwidth of the channel = Total bandwidth of the modulated signals + Guard band
= 55 kHz + 2 kHz
= 57 kHz
Therefore, the bandwidth of the channel is 57 kHz.
Hence, option (D) is the correct answer.
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Similar Electronics and Communication Engineering (ECE) Doubts
Top Courses for Electronics and Communication Engineering (ECE)View all
Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer?
Question Description
Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2025 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer?.
Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2025 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.
Here you can find the meaning of Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Three message signals each band limited to 10 kHz, 10 kHz, and 5 KHz are transmitted through a channel using frequency division multiplexing. The modulation techniques used are any, D513-SC, SSB respectively. The guard band is 2 KHz. Band width of the channel isa)49 kHzb)45 kHzc)53 kHzd)57 kHzCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
|
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
x
![]()
For Your Perfect Score in Electronics and Communication Engineering (ECE)
The Best you need at One Place
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup