Maximum horse power is transmitted by a belt drive when its velocity i...
Power transmitted
where
For maximum power to be transmitted
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Maximum horse power is transmitted by a belt drive when its velocity i...
Maximum Horsepower Transmission in Belt Drive
The maximum horse power that can be transmitted by a belt drive is dependent on various factors such as the velocity of the belt, the tension in the belt, and the centrifugal force acting on the belt. The tight side driving tension in the belt is a crucial factor in determining the maximum horsepower transmission capacity of the belt drive.
Formula
The formula to calculate the tight side driving tension in the belt is given as:
T1 = T2 * e^(μθ)
where T1 is the tight side driving tension in the belt, T2 is the slack side tension in the belt, μ is the coefficient of friction between the belt and the pulley, and θ is the angle of lap.
Centrifugal Tension
The centrifugal tension in the belt is caused by the centrifugal force acting on the belt due to its rotation. This force tends to throw the belt outwards, causing it to stretch and increase in length. The centrifugal tension can be calculated using the following formula:
Tc = (m * v^2) / r
where Tc is the centrifugal tension, m is the mass of the belt per unit length, v is the velocity of the belt, and r is the radius of the pulley.
Equation
When the velocity of the belt is such that the tight side driving tension in the belt is equal to 3 times the centrifugal tension, i.e., T1 = 3Tc, then the maximum horsepower transmission capacity of the belt drive is achieved. This equation can be written as:
T1 = 3 * ((m * v^2) / r)
Hence, the correct answer to the given question is option C, i.e., 3 times the centrifugal tension.
Maximum horse power is transmitted by a belt drive when its velocity i...
Power transmitted
where
For maximum power to be transmitted
also
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