Class 11 Exam > Class 11 Questions > A block is moving on an inclined plane making...
Start Learning for Free
A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is
[jee 2011]
Correct answer is '5N'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A block is moving on an inclined plane making an angle 45º with h...
Most Upvoted Answer
A block is moving on an inclined plane making an angle 45º with h...
Degrees with the horizontal. The block has a weight of 10 N and is subjected to a frictional force of 4 N opposing its motion. To find the block's acceleration, we can break down the forces acting on it and use Newton's second law of motion.
First, let's resolve the weight of the block into components parallel and perpendicular to the inclined plane. The weight acting perpendicular to the plane is equal to the normal force, which is given by:
Normal force = Weight * cos(angle) = 10 N * cos(45°) = 10 N * 0.707 = 7.07 N
Next, let's resolve the weight parallel to the inclined plane. This component of the weight will act down the incline and will be opposed by the frictional force. The component of the weight acting down the incline is:
Weight parallel to the plane = Weight * sin(angle) = 10 N * sin(45°) = 10 N * 0.707 = 7.07 N
Now, let's calculate the net force acting on the block parallel to the inclined plane:
Net force parallel to the plane = Weight parallel to the plane - Frictional force
= 7.07 N - 4 N = 3.07 N
Finally, we can use Newton's second law of motion to find the acceleration of the block:
Net force parallel to the plane = mass * acceleration
3.07 N = mass * acceleration
Since the mass of the block is not given, we cannot determine the exact value of the acceleration without additional information.
First, let's resolve the weight of the block into components parallel and perpendicular to the inclined plane. The weight acting perpendicular to the plane is equal to the normal force, which is given by:
Normal force = Weight * cos(angle) = 10 N * cos(45°) = 10 N * 0.707 = 7.07 N
Next, let's resolve the weight parallel to the inclined plane. This component of the weight will act down the incline and will be opposed by the frictional force. The component of the weight acting down the incline is:
Weight parallel to the plane = Weight * sin(angle) = 10 N * sin(45°) = 10 N * 0.707 = 7.07 N
Now, let's calculate the net force acting on the block parallel to the inclined plane:
Net force parallel to the plane = Weight parallel to the plane - Frictional force
= 7.07 N - 4 N = 3.07 N
Finally, we can use Newton's second law of motion to find the acceleration of the block:
Net force parallel to the plane = mass * acceleration
3.07 N = mass * acceleration
Since the mass of the block is not given, we cannot determine the exact value of the acceleration without additional information.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Top Courses for Class 11View all
A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer?
Question Description
A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer?.
A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer?.
Solutions for A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer?, a detailed solution for A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer? has been provided alongside types of A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is[jee 2011]Correct answer is '5N'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup