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A single-phase half bridge inverter has supply voltage of 200 V. For a load resistance of 10 Ω, the output power is equal to
  • a)
    2000 W
  • b)
    500 W
  • c)
    225 W
  • d)
    1000W
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A single-phase half bridge inverter has supply voltage of 200 V. For a...
Output is a square wave with an amplitude of 100V.
RMS value of a square wave is equal to its peak value.
So, rms value of output voltage is
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Most Upvoted Answer
A single-phase half bridge inverter has supply voltage of 200 V. For a...
Ω, determine the peak output voltage and peak-to-peak output voltage.

Assuming that the load is resistive, the peak output voltage of the half bridge inverter can be calculated as:

Vpeak = Vsupply/2 = 200/2 = 100 V

The peak-to-peak output voltage can be calculated as:

Vpp = 2*Vpeak = 2*100 = 200 V

Therefore, the peak output voltage of the half bridge inverter is 100 V and the peak-to-peak output voltage is 200 V for a load resistance of 10 Ω.
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