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A full-bridge bipolar PWM inverter is fed from a 240 V battery and is driving an RL load. The fundamental output voltage for a modulation index of 0.8 is
  • a)
    135V
  • b)
    215V
  • c)
    205 V
  • d)
    165 V
Correct answer is option 'A'. Can you explain this answer?
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A full-bridge bipolar PWM inverter is fed from a 240 V battery and is ...
The fundamental output voltage for a modulation index of M is
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A full-bridge bipolar PWM inverter is fed from a 240 V battery and is ...
Given information:
- Inverter type: Full-bridge bipolar PWM inverter
- Input voltage: 240 V battery
- Load type: RL
- Modulation index: 0.8
- Required output voltage: Fundamental output voltage

Calculating fundamental output voltage:
- The modulation index is defined as the ratio of the amplitude of the modulating signal to the amplitude of the carrier signal.
- For a full-bridge bipolar PWM inverter, the peak output voltage is equal to the input voltage (240 V).
- The fundamental output voltage can be calculated using the formula: Vf = (4/π) * Vp * m, where Vp is the peak output voltage and m is the modulation index.
- Substituting the given values, we get: Vf = (4/π) * 240 * 0.8 = 135 V.

Therefore, the correct answer is option 'A' (135 V).
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