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A solid cube is placed on a rough horizontal surface.the coefficient of friction between them is mu where mu is less than 1/2 a variable horizontal force is applied on the cube upper surface as shown the maximum acceleration with which it can movie without toppling is?
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A solid cube is placed on a rough horizontal surface.the coefficient o...
**Question Analysis:**

In this question, we are given a solid cube placed on a rough horizontal surface. The coefficient of friction between the cube and the surface is given as μ, where μ < 1/2.="" we="" need="" to="" find="" the="" maximum="" acceleration="" with="" which="" the="" cube="" can="" move="" without="" toppling="" />

**Solution:**

To solve this problem, we need to consider the forces acting on the cube and analyze the conditions for toppling.

**Forces Acting on the Cube:**

1. Weight (mg): The weight of the cube acts vertically downwards.
2. Normal Force (N): The normal force exerted by the surface acts vertically upwards and balances the weight of the cube.
3. Frictional Force (f): The frictional force acts parallel to the surface opposing the motion of the cube.

**Conditions for Toppling:**

For the cube to topple, the torque produced by the weight of the cube about its edge must exceed the torque produced by the frictional force about the same edge.

**Torque due to Weight (τw):**

The torque due to the weight of the cube about its edge is given by τw = mg * h, where h is the height of the cube.

**Torque due to Friction (τf):**

The torque due to the frictional force about the same edge is given by τf = f * d, where d is the distance between the point of application of the frictional force and the edge.

**Condition for No Toppling:**

For the cube to move without toppling, the torque due to the weight must be less than or equal to the torque due to the friction.

τw ≤ τf

mg * h ≤ f * d

**Maximum Frictional Force (fmax):**

The maximum frictional force is given by fmax = μ * N, where N is the normal force.

**Finding Maximum Acceleration (amax):**

The maximum acceleration can be found using Newton's second law:

f = ma

Substituting the value of fmax, we get:

fmax = μ * N = μ * mg

amax = fmax / m = μ * g

Therefore, the maximum acceleration with which the cube can move without toppling is given by amax = μ * g.

**Final Answer:**

The maximum acceleration with which the cube can move without toppling is μ * g.
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A solid cube is placed on a rough horizontal surface.the coefficient of friction between them is mu where mu is less than 1/2 a variable horizontal force is applied on the cube upper surface as shown the maximum acceleration with which it can movie without toppling is?
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A solid cube is placed on a rough horizontal surface.the coefficient of friction between them is mu where mu is less than 1/2 a variable horizontal force is applied on the cube upper surface as shown the maximum acceleration with which it can movie without toppling is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solid cube is placed on a rough horizontal surface.the coefficient of friction between them is mu where mu is less than 1/2 a variable horizontal force is applied on the cube upper surface as shown the maximum acceleration with which it can movie without toppling is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid cube is placed on a rough horizontal surface.the coefficient of friction between them is mu where mu is less than 1/2 a variable horizontal force is applied on the cube upper surface as shown the maximum acceleration with which it can movie without toppling is?.
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