Let x[n] = e-2nu[n] be the input to a system. Which of the following i...
A system is said to be BIBO stable if it’s impulse response is absolutely summable,

Out of all the responses only

is absolutely summable.

Is not absolutely summable it is divergent.
View all questions of this testLet x[n] = e-2nu[n] be the input to a system. Which of the following i...
D) Both 2 and 3.
To determine if the output of a system is bounded, we need to check if the convolution sum is bounded. The convolution sum is given by:
y[n] = ∑(x[k]h[n-k])
For the given input x[n] = e^(-2n)u[n], we can substitute it into the convolution sum:
y[n] = ∑(e^(-2k)u[k]h[n-k])
Let's consider each option:
a) h[n] = n
Substituting this into the convolution sum:
y[n] = ∑(e^(-2k)u[k](n - k))
The sum is not bounded because the term (n - k) is unbounded.
b) h[n] = 1/n
Substituting this into the convolution sum:
y[n] = ∑(e^(-2k)u[k](1/n)(1/(n-k)))
The sum is not bounded because the term 1/(n-k) is unbounded.
c) h[n] = 1/n^2
Substituting this into the convolution sum:
y[n] = ∑(e^(-2k)u[k](1/n^2)(1/(n-k)))
The sum is bounded because both (1/n^2) and (1/(n-k)) are bounded.
Therefore, the impulse response h[n] = 1/n^2 gives the bounded output for the given input x[n] = e^(-2n)u[n].