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The volume of 0.3 M ferrous ammonium sulphate solution required for the completion of redox titration with 20 mL of 0.1 M potassium dichromate solution is ______mL.
Correct answer is between '40,40'. Can you explain this answer?
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The volume of 0.3 M ferrous ammonium sulphate solution required for th...
Calculation of the volume of ferrous ammonium sulphate solution:
Therefore, the volume of 0.3 M ferrous ammonium sulphate solution required for the completion of redox titration with 20 mL of 0.1 M potassium dichromate solution is 40 mL.
- Number of moles of potassium dichromate = (20 mL) x (0.1 mol/L) = 0.002 mol
- From the balanced chemical equation, 1 mole of potassium dichromate reacts with 6 moles of ferrous ammonium sulphate
- Therefore, number of moles of ferrous ammonium sulphate = 6 x 0.002 mol = 0.012 mol
- Concentration of ferrous ammonium sulphate solution = 0.3 mol/L
- Volume of ferrous ammonium sulphate solution required = (0.012 mol) / (0.3 mol/L) = 0.04 L = 40 mL
Therefore, the volume of 0.3 M ferrous ammonium sulphate solution required for the completion of redox titration with 20 mL of 0.1 M potassium dichromate solution is 40 mL.
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The volume of 0.3 M ferrous ammonium sulphate solution required for the completion of redox titration with 20 mL of 0.1 M potassium dichromate solution is ______mL.Correct answer is between '40,40'. Can you explain this answer?
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