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A closed-coil helical spring is subjected to a torque about its axis. The spring wire would experience a
- a)bending stress
- b)direct tensile stress of uniform intensity at its cross-section
- c)direct shear stress
- d)torsional shearing stress
Correct answer is option 'A'. Can you explain this answer?
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A closed-coil helical spring is subjected to a torque about its axis. ...
When a closed coil helical spring, fixed at one end is subjected to a twisting couple about the central axis of the spring, then bending moment will be produced at every cross-section of the spring. The twisting couple will try to wind up or unwind the spring.
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A closed-coil helical spring is subjected to a torque about its axis. ...
Bending stress in a closed-coil helical spring due to torque
When a closed-coil helical spring is subjected to a torque about its axis, the wire experiences bending stress. This is because the torque causes the coils of the spring to twist and deform, which in turn creates a bending moment on the wire.
The bending stress in the wire is a result of the combination of torsional stress and direct stress. The torsional stress arises due to the torque acting on the spring, while the direct stress arises due to the deformation of the spring coils.
The bending stress can be calculated using the following formula:
σb = (M * c) / I
Where,
σb = Bending stress
M = Torque
c = Distance from the neutral axis to the outer edge of the wire
I = Moment of inertia of the wire cross-section
The moment of inertia of the wire cross-section depends on the geometry of the wire and can be calculated using standard formulas.
In general, the bending stress in a closed-coil helical spring due to torque is higher than the stress due to axial loads. This is because the torque causes the coils to twist and deform, which results in a larger moment arm and hence a higher bending moment on the wire.
Therefore, when designing a closed-coil helical spring to withstand torque, it is important to ensure that the wire is strong enough to resist the bending stress that will be generated. This can be achieved by selecting a wire material with a high yield strength and/or by increasing the wire diameter.
When a closed-coil helical spring is subjected to a torque about its axis, the wire experiences bending stress. This is because the torque causes the coils of the spring to twist and deform, which in turn creates a bending moment on the wire.
The bending stress in the wire is a result of the combination of torsional stress and direct stress. The torsional stress arises due to the torque acting on the spring, while the direct stress arises due to the deformation of the spring coils.
The bending stress can be calculated using the following formula:
σb = (M * c) / I
Where,
σb = Bending stress
M = Torque
c = Distance from the neutral axis to the outer edge of the wire
I = Moment of inertia of the wire cross-section
The moment of inertia of the wire cross-section depends on the geometry of the wire and can be calculated using standard formulas.
In general, the bending stress in a closed-coil helical spring due to torque is higher than the stress due to axial loads. This is because the torque causes the coils to twist and deform, which results in a larger moment arm and hence a higher bending moment on the wire.
Therefore, when designing a closed-coil helical spring to withstand torque, it is important to ensure that the wire is strong enough to resist the bending stress that will be generated. This can be achieved by selecting a wire material with a high yield strength and/or by increasing the wire diameter.
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A closed-coil helical spring is subjected to a torque about its axis. The spring wire would experience aa)bending stressb)direct tensile stress of uniform intensity at its cross-sectionc)direct shear stressd)torsional shearing stressCorrect answer is option 'A'. Can you explain this answer?
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