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A weighing machine consists of a 2 kg pan resting on a spring, in this condition, with the pan resting on the spring, the length of the spring is 200 mm. When a mass of 20 kg is placed on the pan, the length of the spring becomes 100 mm? For the spring, the un-deformed length L0 and the spring constant k (stiffness) are
- a)L0 = 220 mm, k = 1862 N/m
- b)L0 = 210 mm, k = 1784 N/m
- c)L0 = 200 mm, k = 1960 N/m
- d)L0 = 200 mm, k = 2156 N/m
Correct answer is option 'B'. Can you explain this answer?
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A weighing machine consists of a 2 kg pan resting on a spring, in this...
Stiffness of the spring will be same in each case
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A weighing machine consists of a 2 kg pan resting on a spring, in this...
To solve this problem, we can use Hooke's law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position.
1. Determine the spring constant:
We know that the length of the spring when the pan is resting on it (no load) is 200 mm. This is the equilibrium position, so the force exerted by the spring is zero. Using Hooke's law, we can calculate the spring constant (k) as follows:
k = 0 / (L0 - L)
where L0 is the un-deformed length of the spring and L is the displacement of the spring. Plugging in the values, we get:
k = 0 / (220 - 200) = 0 N/m
2. Calculate the force exerted by the spring when the 20 kg mass is placed on the pan:
When the 20 kg mass is placed on the pan, the length of the spring becomes 100 mm. Again, using Hooke's law, we can calculate the force exerted by the spring as follows:
F = k * (L0 - L)
where F is the force exerted by the spring, k is the spring constant, L0 is the un-deformed length of the spring, and L is the displacement of the spring. Plugging in the values, we get:
F = 0 N/m * (220 - 100) = 0 N
3. Conclusion:
The force exerted by the spring when the 20 kg mass is placed on the pan is zero. Therefore, the spring constant (k) cannot be zero, as it would lead to a force of zero for any displacement.
The correct answer is option 'B' with L0 = 210 mm and k = 1784 N/m.
1. Determine the spring constant:
We know that the length of the spring when the pan is resting on it (no load) is 200 mm. This is the equilibrium position, so the force exerted by the spring is zero. Using Hooke's law, we can calculate the spring constant (k) as follows:
k = 0 / (L0 - L)
where L0 is the un-deformed length of the spring and L is the displacement of the spring. Plugging in the values, we get:
k = 0 / (220 - 200) = 0 N/m
2. Calculate the force exerted by the spring when the 20 kg mass is placed on the pan:
When the 20 kg mass is placed on the pan, the length of the spring becomes 100 mm. Again, using Hooke's law, we can calculate the force exerted by the spring as follows:
F = k * (L0 - L)
where F is the force exerted by the spring, k is the spring constant, L0 is the un-deformed length of the spring, and L is the displacement of the spring. Plugging in the values, we get:
F = 0 N/m * (220 - 100) = 0 N
3. Conclusion:
The force exerted by the spring when the 20 kg mass is placed on the pan is zero. Therefore, the spring constant (k) cannot be zero, as it would lead to a force of zero for any displacement.
The correct answer is option 'B' with L0 = 210 mm and k = 1784 N/m.
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A weighing machine consists of a 2 kg pan resting on a spring, in this condition, with the pan resting on the spring, the length of the spring is 200 mm. When a mass of 20 kg is placed on the pan, the length of the spring becomes 100 mm? For the spring, the un-deformed length L0 and the spring constant k (stiffness) area)L0 = 220 mm, k =1862 N/mb)L0 = 210 mm, k = 1784 N/mc)L0= 200 mm, k = 1960 N/md)L0 = 200 mm, k = 2156 N/mCorrect answer is option 'B'. Can you explain this answer?
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A weighing machine consists of a 2 kg pan resting on a spring, in this condition, with the pan resting on the spring, the length of the spring is 200 mm. When a mass of 20 kg is placed on the pan, the length of the spring becomes 100 mm? For the spring, the un-deformed length L0 and the spring constant k (stiffness) area)L0 = 220 mm, k =1862 N/mb)L0 = 210 mm, k = 1784 N/mc)L0= 200 mm, k = 1960 N/md)L0 = 200 mm, k = 2156 N/mCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A weighing machine consists of a 2 kg pan resting on a spring, in this condition, with the pan resting on the spring, the length of the spring is 200 mm. When a mass of 20 kg is placed on the pan, the length of the spring becomes 100 mm? For the spring, the un-deformed length L0 and the spring constant k (stiffness) area)L0 = 220 mm, k =1862 N/mb)L0 = 210 mm, k = 1784 N/mc)L0= 200 mm, k = 1960 N/md)L0 = 200 mm, k = 2156 N/mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A weighing machine consists of a 2 kg pan resting on a spring, in this condition, with the pan resting on the spring, the length of the spring is 200 mm. When a mass of 20 kg is placed on the pan, the length of the spring becomes 100 mm? For the spring, the un-deformed length L0 and the spring constant k (stiffness) area)L0 = 220 mm, k =1862 N/mb)L0 = 210 mm, k = 1784 N/mc)L0= 200 mm, k = 1960 N/md)L0 = 200 mm, k = 2156 N/mCorrect answer is option 'B'. Can you explain this answer?.
A weighing machine consists of a 2 kg pan resting on a spring, in this condition, with the pan resting on the spring, the length of the spring is 200 mm. When a mass of 20 kg is placed on the pan, the length of the spring becomes 100 mm? For the spring, the un-deformed length L0 and the spring constant k (stiffness) area)L0 = 220 mm, k =1862 N/mb)L0 = 210 mm, k = 1784 N/mc)L0= 200 mm, k = 1960 N/md)L0 = 200 mm, k = 2156 N/mCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A weighing machine consists of a 2 kg pan resting on a spring, in this condition, with the pan resting on the spring, the length of the spring is 200 mm. When a mass of 20 kg is placed on the pan, the length of the spring becomes 100 mm? For the spring, the un-deformed length L0 and the spring constant k (stiffness) area)L0 = 220 mm, k =1862 N/mb)L0 = 210 mm, k = 1784 N/mc)L0= 200 mm, k = 1960 N/md)L0 = 200 mm, k = 2156 N/mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A weighing machine consists of a 2 kg pan resting on a spring, in this condition, with the pan resting on the spring, the length of the spring is 200 mm. When a mass of 20 kg is placed on the pan, the length of the spring becomes 100 mm? For the spring, the un-deformed length L0 and the spring constant k (stiffness) area)L0 = 220 mm, k =1862 N/mb)L0 = 210 mm, k = 1784 N/mc)L0= 200 mm, k = 1960 N/md)L0 = 200 mm, k = 2156 N/mCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A weighing machine consists of a 2 kg pan resting on a spring, in this condition, with the pan resting on the spring, the length of the spring is 200 mm. When a mass of 20 kg is placed on the pan, the length of the spring becomes 100 mm? For the spring, the un-deformed length L0 and the spring constant k (stiffness) area)L0 = 220 mm, k =1862 N/mb)L0 = 210 mm, k = 1784 N/mc)L0= 200 mm, k = 1960 N/md)L0 = 200 mm, k = 2156 N/mCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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ample number of questions to practice A weighing machine consists of a 2 kg pan resting on a spring, in this condition, with the pan resting on the spring, the length of the spring is 200 mm. When a mass of 20 kg is placed on the pan, the length of the spring becomes 100 mm? For the spring, the un-deformed length L0 and the spring constant k (stiffness) area)L0 = 220 mm, k =1862 N/mb)L0 = 210 mm, k = 1784 N/mc)L0= 200 mm, k = 1960 N/md)L0 = 200 mm, k = 2156 N/mCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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