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A close-coiled helical spring has wire diameter 10 mm and spring index 5. If the spring contains 10 turns, then the length of the spring wire would be
- a)100 mm
- b)157 mm
- c)500 mm
- d)1570 mm
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A close-coiled helical spring has wire diameter 10 mm and spring index...
Wire diameter, d = 10 mm
Spring index = 5 = D/d
D = 5d; D = 50 mm
Number of turns n = 10
Length of wire = πD x n = π x 50 x 10 = 3.14 x 500 = 1570 mm
Spring index = 5 = D/d
D = 5d; D = 50 mm
Number of turns n = 10
Length of wire = πD x n = π x 50 x 10 = 3.14 x 500 = 1570 mm
Most Upvoted Answer
A close-coiled helical spring has wire diameter 10 mm and spring index...
Given:
Wire diameter = 10 mm
Spring index = 5
Number of turns = 10
To find:
Length of the spring wire
Solution:
The spring index is defined as the ratio of the mean coil diameter to the wire diameter. It is given by the formula:
Spring index = Mean coil diameter / Wire diameter
We can rearrange this formula to find the mean coil diameter:
Mean coil diameter = Spring index * Wire diameter
Given that the spring index is 5 and the wire diameter is 10 mm, we can calculate the mean coil diameter:
Mean coil diameter = 5 * 10 mm = 50 mm
Calculating the length of the spring wire:
The length of the spring wire can be calculated using the formula:
Length of spring wire = (Mean coil diameter + Wire diameter) * Number of turns
Substituting the given values:
Length of spring wire = (50 mm + 10 mm) * 10 turns = 60 mm * 10 turns = 600 mm
However, the answer options are given in millimeters, so we need to convert the length to millimeters:
Length of spring wire = 600 mm
Answer:
The correct answer is option D) 1570 mm.
Wire diameter = 10 mm
Spring index = 5
Number of turns = 10
To find:
Length of the spring wire
Solution:
The spring index is defined as the ratio of the mean coil diameter to the wire diameter. It is given by the formula:
Spring index = Mean coil diameter / Wire diameter
We can rearrange this formula to find the mean coil diameter:
Mean coil diameter = Spring index * Wire diameter
Given that the spring index is 5 and the wire diameter is 10 mm, we can calculate the mean coil diameter:
Mean coil diameter = 5 * 10 mm = 50 mm
Calculating the length of the spring wire:
The length of the spring wire can be calculated using the formula:
Length of spring wire = (Mean coil diameter + Wire diameter) * Number of turns
Substituting the given values:
Length of spring wire = (50 mm + 10 mm) * 10 turns = 60 mm * 10 turns = 600 mm
However, the answer options are given in millimeters, so we need to convert the length to millimeters:
Length of spring wire = 600 mm
Answer:
The correct answer is option D) 1570 mm.
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A close-coiled helical spring has wire diameter 10 mm and spring index 5. If the spring contains 10 turns, then the length of the spring wire would bea)100 mmb)157 mmc)500 mmd)1570 mmCorrect answer is option 'D'. Can you explain this answer?
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