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Minimum number of NAND gates required to implement sum in half-adder circuit is:
  • a)
    2
  • b)
    3
  • c)
    4
  • d)
    5
Correct answer is option 'C'. Can you explain this answer?
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Minimum number of NAND gates required to implement sum in half-adder c...
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Minimum number of NAND gates required to implement sum in half-adder c...
Explanation:
A half-adder is a digital circuit that performs addition of two single bits. The two inputs are called A and B, and the two outputs are called Sum and Carry. The truth table for a half-adder is as follows:

| A | B | Sum | Carry |
|---|---|-----|-------|
| 0 | 0 | 0 | 0 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 0 | 1 |

To implement a half-adder circuit using NAND gates, we can use the following logic:

- The Sum output is the NAND of the NAND of A and B, and the NAND of the Sum and the Carry.
- The Carry output is the NAND of the NAND of A and B, and the NAND of the NAND of A and B.

Using this logic, we can draw the following circuit diagram:

![Half-Adder Circuit Diagram using NAND Gates](https://i.imgur.com/5XW0soH.png)

We can see that the circuit requires a total of 4 NAND gates to implement the half-adder. Therefore, the correct answer is option C, i.e., 4.
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Minimum number of NAND gates required to implement sum in half-adder circuit is:a)2b)3c)4d)5Correct answer is option 'C'. Can you explain this answer?
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