Question Description
A particle A moves along a circle of radius R = 50 cm so that its radius vector r relative to the point O (Fig.) rotates with the constant angular velocity w = 0.40 rad/s. Then modulus of the velocity of the particle, and the modulus of its total acceleration will be a)v = 0.4 m/s, a = 0.4 m/s2b)v = 0.32 m/s, a = 0.32 m/s2c)v = 0.32 m/s, a = 0.4 m/s2d)v = 0.4 m/s, a = 0.32 m/s2Correct answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A particle A moves along a circle of radius R = 50 cm so that its radius vector r relative to the point O (Fig.) rotates with the constant angular velocity w = 0.40 rad/s. Then modulus of the velocity of the particle, and the modulus of its total acceleration will be a)v = 0.4 m/s, a = 0.4 m/s2b)v = 0.32 m/s, a = 0.32 m/s2c)v = 0.32 m/s, a = 0.4 m/s2d)v = 0.4 m/s, a = 0.32 m/s2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle A moves along a circle of radius R = 50 cm so that its radius vector r relative to the point O (Fig.) rotates with the constant angular velocity w = 0.40 rad/s. Then modulus of the velocity of the particle, and the modulus of its total acceleration will be a)v = 0.4 m/s, a = 0.4 m/s2b)v = 0.32 m/s, a = 0.32 m/s2c)v = 0.32 m/s, a = 0.4 m/s2d)v = 0.4 m/s, a = 0.32 m/s2Correct answer is option 'D'. Can you explain this answer?.

Solutions for A particle A moves along a circle of radius R = 50 cm so that its radius vector r relative to the point O (Fig.) rotates with the constant angular velocity w = 0.40 rad/s. Then modulus of the velocity of the particle, and the modulus of its total acceleration will be a)v = 0.4 m/s, a = 0.4 m/s2b)v = 0.32 m/s, a = 0.32 m/s2c)v = 0.32 m/s, a = 0.4 m/s2d)v = 0.4 m/s, a = 0.32 m/s2Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of A particle A moves along a circle of radius R = 50 cm so that its radius vector r relative to the point O (Fig.) rotates with the constant angular velocity w = 0.40 rad/s. Then modulus of the velocity of the particle, and the modulus of its total acceleration will be a)v = 0.4 m/s, a = 0.4 m/s2b)v = 0.32 m/s, a = 0.32 m/s2c)v = 0.32 m/s, a = 0.4 m/s2d)v = 0.4 m/s, a = 0.32 m/s2Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A particle A moves along a circle of radius R = 50 cm so that its radius vector r relative to the point O (Fig.) rotates with the constant angular velocity w = 0.40 rad/s. Then modulus of the velocity of the particle, and the modulus of its total acceleration will be a)v = 0.4 m/s, a = 0.4 m/s2b)v = 0.32 m/s, a = 0.32 m/s2c)v = 0.32 m/s, a = 0.4 m/s2d)v = 0.4 m/s, a = 0.32 m/s2Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A particle A moves along a circle of radius R = 50 cm so that its radius vector r relative to the point O (Fig.) rotates with the constant angular velocity w = 0.40 rad/s. Then modulus of the velocity of the particle, and the modulus of its total acceleration will be a)v = 0.4 m/s, a = 0.4 m/s2b)v = 0.32 m/s, a = 0.32 m/s2c)v = 0.32 m/s, a = 0.4 m/s2d)v = 0.4 m/s, a = 0.32 m/s2Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A particle A moves along a circle of radius R = 50 cm so that its radius vector r relative to the point O (Fig.) rotates with the constant angular velocity w = 0.40 rad/s. Then modulus of the velocity of the particle, and the modulus of its total acceleration will be a)v = 0.4 m/s, a = 0.4 m/s2b)v = 0.32 m/s, a = 0.32 m/s2c)v = 0.32 m/s, a = 0.4 m/s2d)v = 0.4 m/s, a = 0.32 m/s2Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A particle A moves along a circle of radius R = 50 cm so that its radius vector r relative to the point O (Fig.) rotates with the constant angular velocity w = 0.40 rad/s. Then modulus of the velocity of the particle, and the modulus of its total acceleration will be a)v = 0.4 m/s, a = 0.4 m/s2b)v = 0.32 m/s, a = 0.32 m/s2c)v = 0.32 m/s, a = 0.4 m/s2d)v = 0.4 m/s, a = 0.32 m/s2Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 11 tests.