A string of mass 100 gm is clamped between two rigid supports a wave o...
Given:
Mass of the string, m = 100 gm = 0.1 kg
Amplitude of the wave, A = 2 mm = 0.002 m
Angular frequency of the wave, ω = 5000 rad/s
To find:
Total energy of the wave in the string
Formula:
Total energy of a wave on a string = 1/2 * μ * v² * A² * ω²
Where, μ = mass per unit length of the string
v = velocity of the wave in the string
Calculation:
1. Calculation of μ:
Mass per unit length of the string, μ = m / L
Where, L = length of the string
As the length of the string is not given, let's assume it to be 1 m (as it doesn't affect the final answer)
μ = 0.1 kg / 1 m = 0.1 kg/m
2. Calculation of v:
The velocity of the wave in the string, v = ω * λ
Where, λ = wavelength of the wave
As the wavelength is not given, we can use the relation between λ and A:
λ = 2 * π * A
λ = 2 * π * 0.002 m
λ = 0.01256 m
v = 5000 rad/s * 0.01256 m = 62.8 m/s
3. Calculation of Total energy:
Total energy of the wave in the string = 1/2 * μ * v² * A² * ω²
Total energy = 0.5 * 0.1 kg/m * (62.8 m/s)² * (0.002 m)² * (5000 rad/s)²
Total energy = 0.5 * 0.1 * 62.8² * 0.002² * 5000²
Total energy = 31.4 J
Therefore, the total energy of the wave in the string is 31.4 J.
A string of mass 100 gm is clamped between two rigid supports a wave o...
The total energy of stationary wave in the string is 1/4KA^2=1/4mw^2A^2
now after putting the values we will get answer =2.5J
with regards
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.