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Let bi > 1 for i = 1, 2, ..., 101. Suppose loge b1, loge b2, ...., loge b101 are in Arithmetic Progression (A.P.) with the common difference loge 2. Suppose a1, a2, ...., a101 are in A.P. such that a1= b1 and a51= b51. If t= b1+b2 + .... + b51 and s= a1+a2+ .... + a53, then (JEE Adv. 2016)a)s > t and a101> b101b)s > t and a101 < b101c)s < t and a101 > b101d)s < t and a101 < b101Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let bi > 1 for i = 1, 2, ..., 101. Suppose loge b1, loge b2, ...., loge b101 are in Arithmetic Progression (A.P.) with the common difference loge 2. Suppose a1, a2, ...., a101 are in A.P. such that a1= b1 and a51= b51. If t= b1+b2 + .... + b51 and s= a1+a2+ .... + a53, then (JEE Adv. 2016)a)s > t and a101> b101b)s > t and a101 < b101c)s < t and a101 > b101d)s < t and a101 < b101Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let bi > 1 for i = 1, 2, ..., 101. Suppose loge b1, loge b2, ...., loge b101 are in Arithmetic Progression (A.P.) with the common difference loge 2. Suppose a1, a2, ...., a101 are in A.P. such that a1= b1 and a51= b51. If t= b1+b2 + .... + b51 and s= a1+a2+ .... + a53, then (JEE Adv. 2016)a)s > t and a101> b101b)s > t and a101 < b101c)s < t and a101 > b101d)s < t and a101 < b101Correct answer is option 'B'. Can you explain this answer?.

Solutions for Let bi > 1 for i = 1, 2, ..., 101. Suppose loge b1, loge b2, ...., loge b101 are in Arithmetic Progression (A.P.) with the common difference loge 2. Suppose a1, a2, ...., a101 are in A.P. such that a1= b1 and a51= b51. If t= b1+b2 + .... + b51 and s= a1+a2+ .... + a53, then (JEE Adv. 2016)a)s > t and a101> b101b)s > t and a101 < b101c)s < t and a101 > b101d)s < t and a101 < b101Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Let bi > 1 for i = 1, 2, ..., 101. Suppose loge b1, loge b2, ...., loge b101 are in Arithmetic Progression (A.P.) with the common difference loge 2. Suppose a1, a2, ...., a101 are in A.P. such that a1= b1 and a51= b51. If t= b1+b2 + .... + b51 and s= a1+a2+ .... + a53, then (JEE Adv. 2016)a)s > t and a101> b101b)s > t and a101 < b101c)s < t and a101 > b101d)s < t and a101 < b101Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Let bi > 1 for i = 1, 2, ..., 101. Suppose loge b1, loge b2, ...., loge b101 are in Arithmetic Progression (A.P.) with the common difference loge 2. Suppose a1, a2, ...., a101 are in A.P. such that a1= b1 and a51= b51. If t= b1+b2 + .... + b51 and s= a1+a2+ .... + a53, then (JEE Adv. 2016)a)s > t and a101> b101b)s > t and a101 < b101c)s < t and a101 > b101d)s < t and a101 < b101Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Let bi > 1 for i = 1, 2, ..., 101. Suppose loge b1, loge b2, ...., loge b101 are in Arithmetic Progression (A.P.) with the common difference loge 2. Suppose a1, a2, ...., a101 are in A.P. such that a1= b1 and a51= b51. If t= b1+b2 + .... + b51 and s= a1+a2+ .... + a53, then (JEE Adv. 2016)a)s > t and a101> b101b)s > t and a101 < b101c)s < t and a101 > b101d)s < t and a101 < b101Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Let bi > 1 for i = 1, 2, ..., 101. Suppose loge b1, loge b2, ...., loge b101 are in Arithmetic Progression (A.P.) with the common difference loge 2. Suppose a1, a2, ...., a101 are in A.P. such that a1= b1 and a51= b51. If t= b1+b2 + .... + b51 and s= a1+a2+ .... + a53, then (JEE Adv. 2016)a)s > t and a101> b101b)s > t and a101 < b101c)s < t and a101 > b101d)s < t and a101 < b101Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Let bi > 1 for i = 1, 2, ..., 101. Suppose loge b1, loge b2, ...., loge b101 are in Arithmetic Progression (A.P.) with the common difference loge 2. Suppose a1, a2, ...., a101 are in A.P. such that a1= b1 and a51= b51. If t= b1+b2 + .... + b51 and s= a1+a2+ .... + a53, then (JEE Adv. 2016)a)s > t and a101> b101b)s > t and a101 < b101c)s < t and a101 > b101d)s < t and a101 < b101Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.