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A 10 kVA, 400 V/200V single phase transformer with 10% impedance draws a steady short circuit line current of
- a)50 A
- b)150 A .
- c)250 A
- d)350 A
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A 10 kVA, 400 V/200V single phase transformer with 10% impedance draws...
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A 10 kVA, 400 V/200V single phase transformer with 10% impedance draws...
Short Circuit Line Current Calculation
Transformer Details:
- Rating: 10 kVA
- Primary Voltage: 400 V
- Secondary Voltage: 200 V
- Impedance: 10%
Formula:
- Short Circuit Line Current = (Rated Voltage on Secondary Side) / [(Impedance %) x (Rated Voltage on Primary Side)]
Calculation:
- Rated Voltage on Secondary Side = 200 V
- Rated Voltage on Primary Side = 400 V
- Impedance % = 10%
Short Circuit Line Current = (200 V) / [(10%) x (400 V)]
= 50 A
Therefore, the steady short circuit line current drawn by the transformer is 250 A (Option C).
Transformer Details:
- Rating: 10 kVA
- Primary Voltage: 400 V
- Secondary Voltage: 200 V
- Impedance: 10%
Formula:
- Short Circuit Line Current = (Rated Voltage on Secondary Side) / [(Impedance %) x (Rated Voltage on Primary Side)]
Calculation:
- Rated Voltage on Secondary Side = 200 V
- Rated Voltage on Primary Side = 400 V
- Impedance % = 10%
Short Circuit Line Current = (200 V) / [(10%) x (400 V)]
= 50 A
Therefore, the steady short circuit line current drawn by the transformer is 250 A (Option C).
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