In a new temperature scale say of the boiling and freezing point of wa...
Introduction
In this question, we need to correlate a new temperature scale with the centigrade scale. The boiling and freezing point of water in the new scale are given as 100 f and 300 f respectively.
Correlation with Centigrade Scale
To correlate the new temperature scale with the centigrade scale, we need to find the values of boiling and freezing point of water in centigrade scale.
Boiling Point of Water
In centigrade scale, the boiling point of water is 100°C. Therefore, we can write:
100 f = 100°C
Freezing Point of Water
In centigrade scale, the freezing point of water is 0°C. Therefore, we can write:
300 f = ?°C
To find the value of freezing point in centigrade scale, we can use the formula:
(f - 32) x 5/9 = C
Where f is the temperature in Fahrenheit scale and C is the temperature in centigrade scale.
Substituting the values, we get:
(300 - 32) x 5/9 = 148.89°C
Therefore, the freezing point of water in the new scale is 148.89°C.
Reading of 0°F on Centigrade Scale
To find the reading of 0°F on the centigrade scale, we can use the formula:
(f - 32) x 5/9 = C
Where f is 0°F and C is the required temperature on centigrade scale.
Substituting the values, we get:
(0 - 32) x 5/9 = -17.78°C
Therefore, the reading of 0°F on the centigrade scale is -17.78°C.
Conclusion
In conclusion, the boiling point of water in the new temperature scale is equivalent to 100°C. The freezing point of water in the new scale is equivalent to 148.89°C. The reading of 0°F on the centigrade scale is -17.78°C.