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A rod of material with E = 200 x 103 MPa and α = 10-3/°C is fixed at both the ends. It is uniformly heated such that the increase in temperature is 30°C. The stress developed in the rod is
  • a)
    6000 N/mm2 (tensile)
  • b)
    6000 N/mm2 (compressive)
  • c)
    2000 N/mm2 (tensile)
  • d)
    2000 N/mm2 (compressive)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A rod of material with E = 200 x 103 MPa and α = 10-3/°C is ...
Thermal stress (σ) = αEΔT

The stress induced is compressive in nature as a compressive force is exerted by the supports which prevent increase in length due to increase is temperature.
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Most Upvoted Answer
A rod of material with E = 200 x 103 MPa and α = 10-3/°C is ...
A cross-sectional area of 0.02 m^2 is subjected to a tensile force of 100 kN. The stress on the rod can be calculated using the formula:

Stress = Force / Area

Plugging in the values:

Stress = 100 kN / 0.02 m^2

Converting kN to N:

Stress = 100,000 N / 0.02 m^2

Stress = 5,000,000 N/m^2

The stress on the rod is 5,000,000 N/m^2.
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A rod of material with E = 200 x 103 MPa and α = 10-3/°C is fixed at both the ends. It is uniformly heated such that the increase in temperature is 30°C. The stress developed in the rod isa)6000 N/mm2 (tensile)b)6000 N/mm2 (compressive)c)2000 N/mm2 (tensile)d)2000 N/mm2 (compressive)Correct answer is option 'B'. Can you explain this answer?
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