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Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is
(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)
  • a)
    1.5 g
  • b)
    2.4 g
  • c)
    1.8 g
  • d)
    1.0 g
Correct answer is option 'B'. Can you explain this answer?
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Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w&rsq...
Moles at equilibrium = 1 – 2α + α = 1 - α
2α = 0.8, α = 0.4
Moles at equilibrium = 0.6
i = 0.6
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Most Upvoted Answer
Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w&rsq...
The dimerisation process involves two molecules of benzoic acid joining together through a hydrogen bond. The carboxyl group (-COOH) of one molecule interacts with the aromatic ring of the other molecule, forming a stable dimer. The dimerisation reaction can be represented as follows:

2C6H5COOH ⇌ (C6H5COOH)2

The equilibrium constant for this reaction is dependent on the concentration of benzoic acid and the temperature. At room temperature, the equilibrium constant is approximately 10^3, indicating that the dimerisation reaction is favored. This is due to the strong intermolecular forces between the carboxyl group and the aromatic ring, which make the dimer more stable than individual molecules.
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Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)a)1.5 gb)2.4 gc)1.8 gd)1.0 gCorrect answer is option 'B'. Can you explain this answer?
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Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)a)1.5 gb)2.4 gc)1.8 gd)1.0 gCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)a)1.5 gb)2.4 gc)1.8 gd)1.0 gCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)a)1.5 gb)2.4 gc)1.8 gd)1.0 gCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)a)1.5 gb)2.4 gc)1.8 gd)1.0 gCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)a)1.5 gb)2.4 gc)1.8 gd)1.0 gCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)a)1.5 gb)2.4 gc)1.8 gd)1.0 gCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)a)1.5 gb)2.4 gc)1.8 gd)1.0 gCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)a)1.5 gb)2.4 gc)1.8 gd)1.0 gCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Molecules of benzoic acid (C6H5COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is(Given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)a)1.5 gb)2.4 gc)1.8 gd)1.0 gCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
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