If the sum of two numbers is 25 and their product is 156. Find the lar...
Let the larger number be ‘x’
Smaller number = 25 - x
Product = x(25 - x) = 156
⇒ 25x - x2 = 156
⇒ x2 - 25x + 156 = 0
⇒ x2 - 12x - 13x + 156 = 0
⇒ x (x - 12) - 13(x - 12) = 0
⇒ (x - 12)(x - 13) = 0
⇒ x = 12, 13
Smaller number = 25 - x = 13, 12
∵ x is the larger number
∴ The larger number = 13
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If the sum of two numbers is 25 and their product is 156. Find the lar...
Let's assume the two numbers as x and y.
Given:
Sum of two numbers = 25
Product of two numbers = 156
1. Formulating the equations:
From the given information, we can form the following equations:
x + y = 25 ...(Equation 1)
xy = 156 ...(Equation 2)
2. Solving the equations:
To find the larger number, we need to determine the values of x and y. We can solve the equations simultaneously.
From Equation 1, we can express x in terms of y:
x = 25 - y
Substituting this value of x in Equation 2, we get:
(25 - y)y = 156
Expanding the equation:
25y - y^2 = 156
Rearranging the equation:
y^2 - 25y + 156 = 0
3. Factorizing the quadratic equation:
To solve the quadratic equation, we need to factorize it.
The factors of 156 that add up to -25 are -13 and -12.
Therefore, the quadratic equation can be factored as:
(y - 13)(y - 12) = 0
Setting each factor equal to zero, we get two possible values for y:
y - 13 = 0 => y = 13
y - 12 = 0 => y = 12
4. Determining the larger number:
Now that we have found the possible values of y, we can substitute them back into Equation 1 to find the corresponding values of x.
For y = 13:
x = 25 - y
x = 25 - 13
x = 12
For y = 12:
x = 25 - y
x = 25 - 12
x = 13
Comparing the values of x and y, we can see that the larger number is 13.
Therefore, the correct answer is option C) 13.