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The emf per turn of a single phase 10 kVA, 2200/220 V, 50 Hz transformer is 10 V. The net cross-sectional area of core for a maximum flux density of 1.5 T is
- a)300 cm2
- b)200 cm2
- c)100 cm2
- d)25 cm2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The emf per turn of a single phase 10 kVA, 2200/220 V, 50 Hz transform...
Maximum flux,
∴ New cross-sectional area of core,
∴ New cross-sectional area of core,
Most Upvoted Answer
The emf per turn of a single phase 10 kVA, 2200/220 V, 50 Hz transform...
Solution:
Given data:
EMF per turn, E = 10 V
Single-phase transformer rating, S = 10 kVA
Primary voltage, V1 = 2200 V
Secondary voltage, V2 = 220 V
Frequency, f = 50 Hz
Maximum flux density, Bm = 1.5 T
1. Calculation of the number of turns:
The EMF per turn of the transformer is given as 10 V. Therefore, the total number of turns required on the transformer can be calculated as:
E = 4.44fΦNT
10 = 4.44 × 50 × Φ × N
N = 10/(4.44 × 50 × Φ)
N = 225/Φ
2. Calculation of the flux density:
The flux density of the transformer can be calculated as:
V1/N1 = V2/N2
2200/N1 = 220/N2
N1/N2 = 10
Φ = Bm × A
Bm = Φ/A
Φ = Bm × A = Bm × (2l + 2b)/2
Φ = Bm × (2l + 2b)/2 = Bm × l × b
Bm = Φ/(l × b)
Bm = V1/(4.44fN1A)
3. Calculation of the core area:
The area of the core required for the maximum flux density of 1.5 T can be calculated as:
A = V1/(4.44fN1Bm)
A = 2200/(4.44 × 50 × 225/Φ × 1.5)
A = 300 cm2
Therefore, the correct option is A) 300 cm2.
Given data:
EMF per turn, E = 10 V
Single-phase transformer rating, S = 10 kVA
Primary voltage, V1 = 2200 V
Secondary voltage, V2 = 220 V
Frequency, f = 50 Hz
Maximum flux density, Bm = 1.5 T
1. Calculation of the number of turns:
The EMF per turn of the transformer is given as 10 V. Therefore, the total number of turns required on the transformer can be calculated as:
E = 4.44fΦNT
10 = 4.44 × 50 × Φ × N
N = 10/(4.44 × 50 × Φ)
N = 225/Φ
2. Calculation of the flux density:
The flux density of the transformer can be calculated as:
V1/N1 = V2/N2
2200/N1 = 220/N2
N1/N2 = 10
Φ = Bm × A
Bm = Φ/A
Φ = Bm × A = Bm × (2l + 2b)/2
Φ = Bm × (2l + 2b)/2 = Bm × l × b
Bm = Φ/(l × b)
Bm = V1/(4.44fN1A)
3. Calculation of the core area:
The area of the core required for the maximum flux density of 1.5 T can be calculated as:
A = V1/(4.44fN1Bm)
A = 2200/(4.44 × 50 × 225/Φ × 1.5)
A = 300 cm2
Therefore, the correct option is A) 300 cm2.
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The emf per turn of a single phase 10 kVA, 2200/220 V, 50 Hz transformer is 10 V. The net cross-sectional area of core for a maximum flux density of 1.5 T isa)300 cm2 b)200 cm2c)100 cm2 d)25 cm2Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The emf per turn of a single phase 10 kVA, 2200/220 V, 50 Hz transformer is 10 V. The net cross-sectional area of core for a maximum flux density of 1.5 T isa)300 cm2 b)200 cm2c)100 cm2 d)25 cm2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The emf per turn of a single phase 10 kVA, 2200/220 V, 50 Hz transformer is 10 V. The net cross-sectional area of core for a maximum flux density of 1.5 T isa)300 cm2 b)200 cm2c)100 cm2 d)25 cm2Correct answer is option 'A'. Can you explain this answer?.
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