Five years ago a mother was 7 times as old as her daughter five years hence she will be 3 times as old as her daughter find their present ages?

Question

Answer

Answer

Answer

Problem: A mother was 7 times as old as her daughter five years ago. Five years hence she will be 3 times as old as her daughter. Find their present ages.

Solution:

Let the present age of the daughter be 'x' years old.
Then, the present age of the mother will be '7x' years old.

Five years ago:
Daughter's age = x - 5
Mother's age = 7x - 5

Five years hence:
Daughter's age = x + 5
Mother's age = 7x + 5

According to the problem, five years ago the mother was 7 times as old as her daughter. So, we can write the equation as:

7x - 5 = (x - 5) * 7

Simplifying the above equation, we get:

6x = 40

x = 6.67

So, the present age of the daughter is 6.67 years.

To find the present age of the mother, we can substitute x = 6.67 in the equation:

Mother's age = 7x

Mother's age = 7 * 6.67

Mother's age = 46.67

Therefore, the present age of the mother is 46.67 years.

Answer:
Present age of the daughter = 6.67 years
Present age of the mother = 46.67 years.

Answer

Let the present age of the daughter be 'x'.

♦ 5 years ago,

Daughter's age = x - 5

Mother's age = 7(x - 5) = 7x - 35

♦ At present,

Daughter's age = x - 5 + 5 = x

Mother's age = 7x - 35 + 5 = 7x - 30

♦ 5 years hence,

Daughter's age = x + 5

Mother's age = 7x - 30 + 5 = 7x - 25

♦ But according to the question, after 5 years, mother will be thrice daughter's age.

→→→ 7x - 25 = 3(x + 5)

=> 7x - 25 = 3x + 15

=> 7x - 3x = 15 + 25

=> 4x = 40

=> x = 40/4

=> x = 10

•�• Daughter's present age = x = 10 years.

•�• Mother's present age = 7x - 30 = 7(10) - 30 = 70 - 30 = 40 years.

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