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The sum of the digit of a two digit number is 10 the number obtained by interchanging the digit exceeds the original number by 36 find the original number?
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The sum of the digit of a two digit number is 10 the number obtained b...
Problem Statement:
The sum of the digits of a two-digit number is 10. The number obtained by interchanging the digits exceeds the original number by 36. Find the original number.

Solution:

Let's assume the two-digit number to be 10x + y, where x represents the tens digit and y represents the units digit.

First Condition: The sum of the digits of the number is 10.
According to the problem statement, we have the equation:
x + y = 10

Second Condition: The number obtained by interchanging the digits exceeds the original number by 36.
The number obtained by interchanging the digits is 10y + x.
According to the problem statement, we have the equation:
10y + x = 10x + y + 36

Solving the Equations:
We can solve the system of equations by substituting the value of x from the first equation into the second equation.

Substituting x = 10 - y into the second equation, we get:
10y + (10 - y) = 10(10 - y) + y + 36
10y + 10 - y = 100 - 10y + y + 36
9y + 10 = 100 - 9y + 36
18y + 10 = 136 - 9y
27y = 126
y = 126 / 27
y = 6

Substituting y = 6 into the first equation, we get:
x + 6 = 10
x = 10 - 6
x = 4

Therefore, the original number is 10x + y = 10(4) + 6 = 40 + 6 = 46.

Answer:
The original number is 46.
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The sum of the digit of a two digit number is 10 the number obtained b...
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