Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > A coil of 100 turns is wound on a torroidal m... Start Learning for Free
A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)
- a)210 volt
- b)230 volt
- c)115 volt
- d)Zero volt
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A coil of 100 turns is wound on a torroidal magnetic core having a rel...
Free Test
FREE
| Start Free Test |
Community Answer
A coil of 100 turns is wound on a torroidal magnetic core having a rel...
To find the voltage across the coil, we need to calculate the flux linking the coil and then use Faraday's law of electromagnetic induction.
The flux linking the coil, Φ, is given by the product of the number of turns in the coil, N, and the magnetic flux per turn, Φ per turn:
Φ = N * Φ per turn.
The magnetic flux per turn, Φ per turn, is related to the current in the coil and the reluctance of the core by the equation:
Φ per turn = (current * reluctance) / number of turns.
Substituting the given values, we have:
Φ per turn = (5 A * 104 AT/Wb) / 100 turns
= 5.2 AT/Wb.
Now, the rate of change of flux linking the coil, dΦ/dt, is related to the voltage across the coil, V, by Faraday's law of electromagnetic induction:
V = -N * (dΦ/dt).
Taking the derivative of the equation for Φ per turn with respect to time, we have:
dΦ/dt = (d/dt) [(current * reluctance) / number of turns]
= (reluctance / number of turns) * (d/dt) [current].
Substituting the given values, we have:
dΦ/dt = (104 AT/Wb / 100 turns) * (200 A/s)
= 208 AT/Wb/s.
Finally, we can use this value to find the voltage across the coil:
V = -N * (dΦ/dt)
= -100 turns * (208 AT/Wb/s)
= -20800 V.
Since voltage cannot be negative, the voltage across the coil would be 20800 V.
The flux linking the coil, Φ, is given by the product of the number of turns in the coil, N, and the magnetic flux per turn, Φ per turn:
Φ = N * Φ per turn.
The magnetic flux per turn, Φ per turn, is related to the current in the coil and the reluctance of the core by the equation:
Φ per turn = (current * reluctance) / number of turns.
Substituting the given values, we have:
Φ per turn = (5 A * 104 AT/Wb) / 100 turns
= 5.2 AT/Wb.
Now, the rate of change of flux linking the coil, dΦ/dt, is related to the voltage across the coil, V, by Faraday's law of electromagnetic induction:
V = -N * (dΦ/dt).
Taking the derivative of the equation for Φ per turn with respect to time, we have:
dΦ/dt = (d/dt) [(current * reluctance) / number of turns]
= (reluctance / number of turns) * (d/dt) [current].
Substituting the given values, we have:
dΦ/dt = (104 AT/Wb / 100 turns) * (200 A/s)
= 208 AT/Wb/s.
Finally, we can use this value to find the voltage across the coil:
V = -N * (dΦ/dt)
= -100 turns * (208 AT/Wb/s)
= -20800 V.
Since voltage cannot be negative, the voltage across the coil would be 20800 V.
 | Explore Courses for Electrical Engineering (EE) exam |  |
Top Courses for Electrical Engineering (EE)View all
Top Courses for Electrical Engineering (EE)
Question Description
A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer?.
A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A coil of 100 turns is wound on a torroidal magnetic core having a reluctance of 104 AT/Wb. When the coil current is 5 A and is increasing at the rate of 200 A/s, the voltage across the coil would be (assume coil resistance to be 2 Ω)a)210 voltb)230 voltc)115 voltd)Zero voltCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
| Explore Courses for Electrical Engineering (EE) exam | |
Top Courses for Electrical Engineering (EE)
Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
