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In laminar flow through a circular pipe, the discharge varies
  • a)
    linearly with fluid density
  • b)
    inversely with pressure drop
  • c)
    direclty as square of pipe radius
  • d)
    inversely with fluid viscosity
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In laminar flow through a circular pipe, the discharge variesa)linearl...

So,

Q ∝ pressure gradient and Q ∝ R4
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Most Upvoted Answer
In laminar flow through a circular pipe, the discharge variesa)linearl...
Explanation:


The discharge in laminar flow through a circular pipe is given by the Hagen-Poiseuille equation.

Hagen-Poiseuille equation:


The Hagen-Poiseuille equation describes the laminar flow of a fluid through a circular pipe. It is given by:

Q = (πr⁴ΔP)/(8ηL)

Where,
Q = Discharge
r = Radius of the pipe
ΔP = Pressure drop
η = Fluid viscosity
L = Length of the pipe

Inference:


From the above equation, we can see that the discharge varies inversely with the fluid viscosity. This means that if the fluid viscosity increases, the discharge will decrease and vice versa. Therefore, option D is the correct answer.

Conclusion:


In conclusion, the discharge in laminar flow through a circular pipe varies inversely with the fluid viscosity.
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In laminar flow through a circular pipe, the discharge variesa)linearly with fluid densityb)inversely with pressure dropc)direclty as square of pipe radiusd)inversely with fluid viscosityCorrect answer is option 'D'. Can you explain this answer?
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