Coefficient of x50 in (1 + x)1000 + 2x(1 + x)999 + 3x(1 + x)998 + .......
Take (1 + x)1000 as common, after simplification it becomes (1 + x)1000 coefficient of x50 is 1002C50
View all questions of this testCoefficient of x50 in (1 + x)1000 + 2x(1 + x)999 + 3x(1 + x)998 + .......
To find the coefficient of x^50 in the given expression, we need to identify the terms that contain x^50 and determine their coefficients.
Let's break down the given expression into individual terms:
Term 1: (1 x)^1000
Term 2: 2x(1 x)^999
Term 3: 3x(1 x)^998
...
The general term can be written as kx(1 x)^(1000-k), where k represents the coefficient of the term.
To find the coefficient of x^50, we need to solve the equation 1000 - k = 50, which gives us k = 950.
Now, let's calculate the coefficient of x^50 in the first term:
Coefficient of x^50 in (1 x)^1000 = (1000C50) = 1000! / (50! * 950!)
Similarly, the coefficient of x^50 in the second term is:
Coefficient of x^50 in 2x(1 x)^999 = 2 * (999C49) = 2 * 999! / (49! * 950!)
And for the third term:
Coefficient of x^50 in 3x(1 x)^998 = 3 * (998C48) = 3 * 998! / (48! * 950!)
We can observe that the coefficient of x^50 increases by 1 for each subsequent term.
Therefore, the coefficient of x^50 in the given expression can be calculated as:
1000! / (50! * 950!) + 2 * 999! / (49! * 950!) + 3 * 998! / (48! * 950!) + ...
This can be simplified by factoring out 950! from each term:
950! * [1000/(50! * 950!) + 2 * 999/(49! * 950!) + 3 * 998/(48! * 950!) + ...]
Simplifying further, we get:
950! * [1000/(50!) + 999/(49!) + 998/(48!) + ...]
This can be written as:
950! * [Summation of (1000-k)/(k!) from k = 0 to 950]
Using the formula for the sum of a series, we can rewrite it as:
950! * [1001C51]
Therefore, the coefficient of x^50 in the given expression is 1001C51 or option 'C'.