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For an element under the effect of biaxial state of normal stresses, the normal stress on 45° plane is equal to
  • a)
    differences of normal stresses
  • b)
    sum of normal stresses
  • c)
    half the sum of normal stresses
  • d)
    half the difference of normal stresses
Correct answer is option 'C'. Can you explain this answer?
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For an element under the effect of biaxial state of normal stresses, t...
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In a biaxial state of normal stresses, there are two normal stresses acting on the element in perpendicular directions. Let's denote these stresses as σ1 and σ2, with σ1 being the larger stress.

The angle at which the normal stress acts on the element can be determined using the Mohr's circle representation of stress. The Mohr's circle is a graphical representation that shows the relationship between normal and shear stresses acting on an element.

In a biaxial state of normal stresses, the Mohr's circle will be an ellipse. The angle at which the normal stress acts on the element can be obtained by drawing a line from the center of the ellipse to the point on the circumference corresponding to the normal stress value. The angle between this line and the horizontal axis represents the direction of the normal stress.

In the case of a biaxial state of normal stresses, the angle at which the normal stress acts on the element will be 45 degrees with respect to the horizontal axis.
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For an element under the effect of biaxial state of normal stresses, the normal stress on 45° plane is equal toa)differences of normal stressesb)sum of normal stressesc)half the sum of normal stressesd)half the difference of normal stressesCorrect answer is option 'C'. Can you explain this answer?
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